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Viefleur [7K]
3 years ago
12

Find the first 4 terms of the Arithmetic sequence. f(n) = f(n-1) + 5 f(1) = -2

Mathematics
1 answer:
nexus9112 [7]3 years ago
5 0
<span>f(n) = f(n-1) + 5   simply means

the next term or f(n), will have a value of
the one before it, or f(n-1), +5

so.. you're looking for the 4th term, that means f(4)
to get 4th term then, that will be the 3rd term plus 5,
whatever the 3rd term is

now... f(1) = -2, simply means, the term 1, or f(1), or first term, is -2

now to find a term value in an arithmetic sequence </span>\bf f(n)=f(1)+(n-1)d\\\\&#10;\begin{cases}&#10;n=n^{th}\ term\to &4\\&#10;f(1)=\textit{first term}\to &-2\\&#10;d=&#10;\begin{array}{llll}&#10;\textit{common difference, or amount}\\&#10;\textit{added to get the next term}&#10;\end{array}\to &5&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\&#10;f(4)=f(1)+(4-1)5

and I'm sure you know what f(1) is, so, just plug it in, to get f(4), or 4th term
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3 0
3 years ago
Annie's great-grandparents lived in a log cabin with their 3 children. The log cabin had a floor area of 450 square feet. The ce
scoray [572]

Answer:

you would have to multiply 450•7

4 0
3 years ago
rank has a circular garden. The area of the garden is 100 ft2. What is the approximate distance from the edge of Frank’s garden
Ray Of Light [21]

It is given that the area of the circular garden = 100 ft^2

Area of circle with radius 'r' = \pi r^2

We have to determine the approximate distance from the edge of Frank’s garden to the center of the garden, that means we have to determine the radius of the circular garden.

Since, area of circular garden = 100

\pi r^2 = 100

\frac{22}{7} \times r^2 = 100

r^2 = \frac{700}{22}

r^2 = 31.8

r = \sqrt{31.8}

So, r = 5.6 ft

r = 6 ft (approximately)

Therefore, the approximate distance from the edge of Frank’s garden to the center of the garden is 6 ft.

So, Option A is the correct answer.

7 0
3 years ago
Read 2 more answers
Log_{7 }(5 - 3x)<br>Find the derivative​
V125BC [204]

Let <em>y</em> be the expression you want to differentiate:

y=\log_7(5-3x) \implies 7^y=5-3x

Now,

7^y=e^{\ln(7^y)}=e^{y\ln(7)}

Use the chain rule to differentiate both sides with respect to <em>x</em> :

\ln(7)e^{y\ln(7)}\dfrac{\mathrm dy}{\mathrm dx}=-3

Solve for d<em>y</em>/d<em>x</em> :

\ln(7)7^y\dfrac{\mathrm dy}{\mathrm dx}=-3

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac3{\ln(7)7^y}

\dfrac{\mathrm dy}{\mathrm dx}=\boxed{-\dfrac3{\ln(7)(5-3x)}}

6 0
3 years ago
Can someone help me with this please
DIA [1.3K]

Answer:

See below

Step-by-step explanation:

The starting point of 0 has a value of 3.  The common difference of 2 is added at each step increse in n.

n f(n)

0 3

1 5

2 7

3 9

4 11

The can be modeled by the equation y = 2x+3

5 0
3 years ago
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