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Wittaler [7]
3 years ago
11

a newborn boa constrictor measure 18 inches long. An adult boa constrictor measures 9 times the lenght of the newborn plus 2 inc

hes. how long is the adult?
Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0
Newborn = 18 inches
adult boa = 9 * 18 + 2 = 164 inches

Since all the information is given, then merely put the necessary facts in order. 

Had the length of the newborn been unknown, it would have been represented by x.

9x + 2 = 164
9x = 164 - 2
9x = 162
9x/9 = 162/9
x = 18
a_sh-v [17]3 years ago
6 0
Start with 18 × 9 = 162
Next add 162 + 2 = 164
Last put 164 on the papper
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Pamela is 15 years younger than Jiri. The sum of their age is 33. what is Jiris age
Luden [163]

Answer:

24 years

Step-by-step explanation:

let jiri's age be x

Pamela's age=x-15

x+x-15=33

2x-15=33

collect the like terms to similar places

2x=33+15

2x=48

x=24

6 0
3 years ago
Find the value of<br> 3a²-4ab-26² when A= -1 and b-4
nata0808 [166]

Answer:

-657

Step-by-step explanation:

a= -1\\b= 4\\

Substituting the value of a and b

3a^{2}-4ab-26^{2}  \\3(-1)^{2} -4(-1)(4)-676\\3-4(-4)-676\\3+16-676\\19-676\\-657

The value of    3a²-4ab-26²  is -657

4 0
3 years ago
What do I need to subtract from to get angle two?
ololo11 [35]
Step 1) Add up the three given angles: 125+109+83 = 317

Step 2) Subtract the result (found in step one) from 360
360 - 317 = 43

The reason for the 360 is because for any four-sided polygon, the angles always add up to 360 degrees. 

The answer is 43

3 0
3 years ago
Which expression has the fewest significant figures?
yanalaym [24]

Hello!

Here are some rules to determine the number of significant figures.

  1. Numbers that are not zero are significant (45 - all are sigfigs)
  2. Zeros between non-zero digits are significant (3006 → all are sigfigs)
  3. Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
  4. Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
  5. Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
  6. In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)

Now, let's find the number of significant figures in each given number.

A). 296.54

Since these digits are all <em>non-zero</em>, there are 5 significant figures.

B). 5003.1

Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.

C). 360.01

Again, the two zeros are between non-zero digits. There are 5 significant figures.

D). 18.3

All of these digits are non-zero, hence, there are 3 significant figures.

Therefore, expression D has the fewest number of significant figures being 3.  

4 0
3 years ago
Read 2 more answers
Suppose a production facility purchases a particular component part in large lots from a supplier. The production manager wants
musickatia [10]

Answer:

We need a sample size of at least 1161.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error for the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.22

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample should she take?

We need a sample size of at least n.

n is found when M = 0.02

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.645\sqrt{\frac{0.22*0.78}{n}}

0.02\sqrt{n} = 1.645\sqrt{0.22*0.78}

\sqrt{n} = \frac{1.645\sqrt{0.22*0.78}}{0.02}

(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.22*0.78}}{0.02})^{2}

n = 1160.88

Rounding up

We need a sample size of at least 1161.

7 0
3 years ago
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