Question

The equation of line LM is y= 5x+4. Write an equation of a line perpendicular to LEM in slope intercept form that contains point (-3, 2)

Answer 1

y= 5x+4 slope = 5
perpendicular to LEM so slope = -1/5

passing thru point (-3, 2)
y = mx + b
2 = -1/5(-3) + b
2 = 3/5 + b
b = 2 - 3/5
b = 10/5 - 3/5
b = 7/5

equation
y = -1/5(x) + 7/5