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stepladder [879]
3 years ago
13

The equation of line LM is y= 5x+4. Write an equation of a line perpendicular to LEM in slope intercept form that contains point

(-3, 2)
Mathematics
1 answer:
natita [175]3 years ago
8 0
<span>y= 5x+4 slope = 5
</span><span>perpendicular to LEM so slope = -1/5

passing thru </span><span>point (-3, 2)
y = mx + b
2 = -1/5(-3) + b
2 = 3/5 + b
b = 2 - 3/5
b = 10/5 - 3/5
b = 7/5

equation
y = -1/5(x) + 7/5</span>
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