Simplify n-3 n-2/n^-6n^5 A) 1/n^-4 B)1/n^4 C)n^-6 D)n^4

Helpppppppppppppppppp

UNO [17]

Answer:

2 solutions

Step-by-step explanation:

Given the expression

2m/2m+3 - 2m/2m-3 = 1

Find the LCM of the expression at the left hand side:

2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1

open the bracket

4m²-6m-4m²-6m/(4m²-9) = 1

Cross multiply

4m²-6m-4m²-6m = 4m² - 9

-12m = 4m² - 9

4m² - 9+12m = 0

4m² +12m-9 = 0

Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2

8 0

3 years ago

There are 10soccer teams in the S-league. Each team plays one match against each of the other teams. How many matches will be pl

ipn [44]

1 - 2 - 3 - 4 - 5 - 6 - 7 - 8 - 9 - 10 are your team numbers
1 - 2
1 - 3
1 - 4
1 - 5
1 - 6
1 - 7
1 - 8
1 - 9
1 - 10
2 - 3
2 - 4
2 - 5
2 - 6
2 - 7
2 - 8
2 - 9
2 - 10
3 - 4
3 - 5
3 - 6
3 - 7
3 - 8
3 - 9
3 - 10
4 - 5
4 - 6
4 - 7
4 - 8
4 - 9
4 - 10
5 - 6
5 - 7
5 - 8
5 - 9
5 - 10
6 - 7
6 - 8
6 - 9
6 - 10
7 - 8
7 - 9
7 - 10
8 - 9
8 - 10
9 - 10

45 matches in all >.< :)

8 0

4 years ago

I dont get how to solve this?

Alex

Answer:

Step-by-step explanation:

In standard form this could be rewritten as | b - 0 | > 6, which in words, says,

"b is greater than 6 units away from 0 on a number line". If b is greater than 6 units away, both positive 6 and negative 6 are 6 units away from 0. Because the values we need are greater than 6 units away from 0, we are starting at both 6 and -6 and moving away from 0.

The "greater than" symbol indicates that this is a disjunction so the word "or" is used as opposed to in a conjunction where the word "and" is used.

Therefore, our solutions are

b < -6 or b > 6, the 3rd choice down

5 0

4 years ago

In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6 years according to the U.S. Depa

marissa [1.9K]

Answer:

The 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Step-by-step explanation:

The confidence interval of the mean is given by the next formula:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$ [1]

We already know (according to the U.S. Department of Justice):

The (population) standard deviation for this case (mean age of an inmate on death row) has a standard deviation of 9.6 years ( $\\ \sigma = 9.6$ years).
The number of observations for the sample taken is $\\ n = 32$ .
The sample mean, $\\ \overline{x} = 38.9$ years.

For $\\ z_{1-\frac{\alpha}{2}}$ , we have that $\\ \alpha = 0.05$ . That is, the level of significance $\\ \alpha$ is 1 - 0.95 = 0.05. In this case, then, we have that the z-score corresponding to this case is:

$\\ z_{1-\frac{\alpha}{2}} = z_{1-\frac{0.05}{2}} = z_{1-0.025} = z_{0.975}$

Consulting a cumulative standard normal table, available on the Internet or in Statistics books, to find the z-score associated to the probability of, $\\ P(z$ , we have that $\\ z = 1.96$ .

Notice that we supposed that the sample is from a population that follows a normal distribution. However, we also have a value for n > 30, and we already know that for this result the sampling distribution for the sample means follows, approximately, a normal distribution with mean, $\\ \mu$ , and standard deviation, $\\ \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}$ .

Having all this information, we can proceed to answer the question.

Constructing the 95% confidence interval for the current mean age of death-row inmates

To construct the 95% confidence interval, we already know that this interval is given by [1]:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

That is, we have:

$\\ \overline{x} = 38.9$ years.

$\\ z_{1-\frac{\alpha}{2}} = 1.96$

$\\ \sigma = 9.6$ years.

$\\ n = 32$

Then

$\\ 38.9 \pm 1.96*\frac{9.6}{\sqrt{32}}$

$\\ 38.9 \pm 1.96*\frac{9.6}{5.656854}$

$\\ 38.9 \pm 1.96*1.697056$

$\\ 38.9 \pm 3.326229$

Therefore, the Upper and Lower limits of the interval are:

Upper limit:

$\\ 38.9 + 3.326229$

$\\ 42.226229 \approx 42.23$ years.

Lower limit:

$\\ 38.9 - 3.326229$

$\\ 35.573771 \approx 35.57$ years.

In sum, the 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Notice that the "mean age of an inmate on death row was 40.7 years in 2002", and this value is between the limits of the 95% confidence interval obtained. So, according to the random sample under study, it seems that this mean age has not changed.

7 0

3 years ago

Please, someone, help me

White raven [17]

Answer:

345

Step-by-step explanation:

8 0

3 years ago

Simplifyn-3 n-2/n^-6n^5A) 1/n^-4B)1/n^4C)n^-6D)n^4