Using derivatives, it is found that:
i)
ii) 9 m/s.
iii)
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:
item i:
Velocity is the <u>derivative of the position</u>, hence:
Item ii:
The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:
Item iv:
The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:
Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Dannng I thought I seen this one before
Answer:
see below
Step-by-step explanation:
Y=x^2
x=-3 -2 -1 0 1 2 3
y=(-3)^2 (-2)^2 (-1)^2 0^2 1^2 2^2 3^2
9 4 1 0 1 4 9
Let <em>f(x)</em> be the sum of the geometric series,
for |<em>x</em>| < 1. Then taking the derivative gives the desired sum,
Answer: x = -6
Step-by-step explanation: The problem gave us the y value, so we can just substitute it into the equation and solve it.
y = x - 6
y = 2x
2x = x - 6 (substitute the y value into the equation)
1x = -6 (subtract x on each side)
x = -6 (1x is basically saying x so you do not need to divide)