Answer:
combined variation
Step-by-step explanation:
we have
we know that
a)<u> in the interval </u>----> (0,∞)
If the value of x increase the value of y increase
so
Is a direct variation
b) <u>in the interval -</u>---> (-∞,0)
If the value of x increase the value of y decrease
so
Is a inverse variation
therefore
Is a combined variation
We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
11 because -7 subtracted by 4 add kore to the 7 so think of it this way -7 is a bad guy and 4 is a bad guy to because its a subtraction so if both bad guys combine you get 11 because a negative with negative makes a positive so its 11
Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
Step-by-step explanation:
hope this helps
Answer:
∴ ∑₁⁸i = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8
Step-by-step explanation:
Given:
To Find:
∑₁⁸i =?
Solution:
Σ This symbol called Sigma means "summation up"
∴ ∑ n mean sum for all n
But if ∑₁³n means Sum for n=1 , 2 ,and 3 ADD
∴ ∑₁³n = 1 + 2 + 3
∴ ∑₁⁸i = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8
