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Marina86 [1]
3 years ago
6

For each of the three products that are observed in the NMR spectrum, there is a diagnostic proton that can be used to accuratel

y calculate the product ratios. Calculate the percentage of the mixture that is o-bromoaniline. To answer this question correctly, you will need to use the BEST diagnostic signals for each isomer.

Engineering
1 answer:
Aloiza [94]3 years ago
6 0

Answer:

The percentage of the o-bromoaniline = 14.7%

Explanation:

Find attached of the calculation and also the NMR spectrum that was used.

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This is a classification of back pain based on duration. A) AcuteB) RecurrentC) ChronicD) All of the above
butalik [34]

Answer:

D) All of the above.

4 0
3 years ago
Air at 105 kPa and 37° C flows upward through a6-cm-diameter inclined duct at a rate of 65 L/s. The duct diameter is then reduce
yaroslaw [1]

Answer:

0.129 m

Explanation:

See attached picture for step by step explanation.

5 0
3 years ago
Limestone scrubbing is used to remove SO2 in a flue gas desulfurization (FGD) system. Relevant reactions are given below. A lime
lord [1]

Answer:

hello some data related to your question is missing attached below is the missing data

answer : 63700 Ib/hr

Explanation:

Given data :

Limestone mix : consists of  94% CaCO3  and 6% inert material

Actual feed rate = 36,000 Ib/hr

SO2 in flue gas = 20,314 Ib/hr

FGD efficiency = 97%

resulting sludge contains 58% solids

<u>Calculate the Total sludge production rate </u>

First : determine  SO2 removed in sludge

 = 0.97 * 20314

 = 19704.58 Ib/hr

next : moles of SO2 removed

= 19704.58 / 64 Ib/ Ib mol

= 307.88 Ib mol / hr

also  moles of CaSO3 produced = 307.88 Ib mol / hr

mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr

Therefore Total sludge production rate

= 36946.09 / 0.58

= 63700.15  Ib/hr

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7 0
3 years ago
_______is defined as the use of statistical techniques to control a process or production method
Wittaler [7]

Answer:

Statistical process control

Explanation:

The answer for the given blank is "Statistical process control".

The Statistical process control is the method that is applied by the employs to control the quality of the process and also, to monitor and control the process.

The Statistical process control helps in ensuring the efficiency of the process and ensuring the waste production is less.

8 0
4 years ago
An insulated piston-cylinder device contains 0.15 of saturated refrigerant-134a vapor at 0.8 MPa pressure. The refrigerant is no
Stells [14]

Answer:

Assumption:

1. The kinetic and potential energy changes are negligible

2. The cylinder is well insulated and thus heat transfer is negligible.

3. The thermal energy stored in the cylinder itself is negligible.

4. The process is stated to be reversible

Analysis:

a. This is reversible adiabatic(i.e isentropic) process and thus s_{1} =s_{2}

From the refrigerant table A11-A13

P_{1} =0.8MPa   \left \{ {{ {{v_{1}=v_{g}  @0.8MPa =0.025645 m^{3/}/kg } } \atop { {{u_{1}=u_{g}  @0.8MPa =246.82 kJ/kg } -   also  {{s_{1}=s_{g}  @0.8MPa =0.91853 kJ/kgK } } \right.

sat vapor

m=\frac{V}{v_{1} } =\frac{0.15}{0.025645} =5.8491 kg\\and \\\\P_{2} =0.2MPa  \left \{ {{x_{2} =\frac{s_{2} -s_{f} }{s_{fg }}=\frac{0.91853-0.15449}{0.78339}   = 0.9753 \atop {u_{2} =u_{f} +x_{2} }(u_{fg}) =  38.26+0.9753(186.25)= 38.26+181.65 =219.9kJ/kg \right. \\s_{1} = s_{2}

T_{2} =T_{sat @ 0.2MPa} = -10.09^{o}  C

b.) We take the content of the cylinder as the sysytem.

This is a closed system since no mass leaves or enters.

Hence, the energy balance for adiabatic closed system can be expressed as:

E_{in} - E_{out}  =ΔE

w_{b, out}  =ΔU

w_{b, out} =m([tex]u_{1} -u_{2)

w_{b, out}  = workdone during the isentropic process

=5.8491(246.82-219.9)

=5.8491(26.91)

=157.3993

=157.4kJ

4 0
3 years ago
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