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xxMikexx [17]
3 years ago
15

When CO2 rises, temperature rises. Why do you think this is?

Engineering
1 answer:
icang [17]3 years ago
6 0

Answer:

The warming causes the oceans to release CO2. The CO2 amplifies the warming and mixes through the atmosphere, spreading warming throughout the planet. So CO2 causes warming AND rising temperature causes CO2 rise. Overall, about 90% of the global warming occurs after the CO2 increase.

Explanation:

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Estimate the quantity of soil to be excavated from the borrow pit​
Serggg [28]

Answer

1056

Explanation:

for example

A soil is to be excavated from a borrow pit which has a density of 1.75g/cc and water content of 12%. The G is 2.7 the soil is compacted to that water content of 18% and dry density of 1.65g/cc. for 1000 m3 of soil used in fill estimate

Quantity of soil to be excavated from pit in m3

6 0
3 years ago
A multipurpose transformer has a secondary coil with several points at which a voltage can be extracted, giving outputs of 5.60,
Rudik [331]

Answer:

for 5.6V 9 turns, for 12.0V 19 turns, for 480V 755 turns

Explanation:

Vp/Vs= Np/Ns

Vp: Primary voltage

Vs: Secondary Voltage

Np: number of turns on primary side

Ns: number of turns on secondary side

for output 5.6V

140/5.6= 220/Ns

Ns= 8.8 or 9 Turns

for output 12.0V

140/12= 220/Ns

Ns= 18.9 or 19 turns

for output 480V

140/480= 220/Ns

Ns= 754.3 or 755 turns

4 0
4 years ago
A motor vehicle engine operating with a diesel engine takes in atmospherics air at a temperature of 30°C and pressure of 1 bar.
nydimaria [60]

Answer:

η=0.568

Explanation:

At inlet condition

temperature = 30 C and pressure P=1 bar

The maximum temperature = 13456 C

Compression ratio r= 12

We know that for process 1-2

\dfrac{T_2}{T_1}=r^{\gamma -1}

\dfrac{T_2}{303}=12^{1.4 -1}

T_2=818.68 K

Now for process 2-3

\dfrac{T_3}{T_2}=\dfrac{V_3}{V_2}

\dfrac{273+1345}{818.86}=\dfrac{V_3}{V_2}

\dfrac{V_3}{V_2}=1.97

So the cut off ratio ρ=1.97

Efficiency of diesel engine

\eta =1-\dfrac{\rho ^{\gamma}-1}{r^{\gamma -1}\gamma \left (\rho -1\right )}

Now put the values

\eta =1-\dfrac{1.97 ^{1.4}-1}{12^{1.4-1}\times 1.4\times \left (1.97 -1\right )}

   ⇒η=0.568

So the efficiency is 56.8%.

4 0
3 years ago
Create a program, using at least one For Loop, that displays the Sales Amounts in each of 4 regions during a period of three mon
kari74 [83]

Answer:

C++ code explained below

Explanation:

/*C++ program that prompts sales for four regions of three sales and prints

the sales values to console */

#include<iostream>

#include<iomanip>

#include<cstring>

using namespace std;

int main()

{

  //set constant values

  const int SALES=3;

  const int REGIONS=4;

  //create an array of four regions

  string regionNames[]={"Region 1","Region 2","Region 3","Region 4"};

  //create a 2D array to read sales

  int sales[REGIONS][SALES];

  //read sales for four regions

  for(int region=0;region<REGIONS;region++)

  {

      cout<<regionNames[region]<<endl;

      for(int sale=0;sale<SALES;sale++)

      {

          cout<<"Enter sales ";

          cin>>sales[region][sale];

      }

  }

  //print sales

  for(int region=0;region<REGIONS;region++)

  {

      cout<<regionNames[region]<<"-";

      for(int sale=0;sale<SALES;sale++)

      {

          cout<<setw(5)<<sales[region][sale];

      }

      cout<<endl;

  }

  //pause program output on console

  system("pause");

  return 0;

}

5 0
4 years ago
When laying out the walls, the first thing we do is put the top plate and the sole plate together. We then look at the print and
dedylja [7]

Answer: A wall is a collection of studs (usually sized 2×4 or 2×6) equally spaced (usually 16 in. or 24 in. on center) and sandwiched between top and bottom plates. The top plate can be either single or double. Double plating is most common on load-bearing walls unless the roof rafters or trusses and floor joists stack directly over the studs in the wall, then a single top plate can be used.

Large openings in the wall are made for windows and doors. When the opening is greater in width than the stud spacing — and most windows are wider than 24 in. — then a header must be inserted to carry the load of the interrupted stud(s). A header is a simple beam sized to support the load above the opening it spans.The header is supported by a jack stud at each end. Jacks, sometimes called trimmers, fit under each end of a header, and they transfer the load that the header carries down to the bottom plate and the framing beneath. Nailed to the jacks are full-height studs called king studs; they support the assembly between the plates. Sometimes jacks must be doubled on wide openings so there’s enough supporting surface for the header to bear on. Jacks can be replaced with a steel header hanger attached to the king stud.

Saddles and cripples

A saddle (also called a sill) forms the bottom of a window opening. It’s a piece of 2x stock laid flat and nailed between the jacks. Cripples are short pieces of 2x stock that run underneath the saddle. And, depending on a header’s height, cripples can run from the header to the plate. Cripples are located at the points where a common stud would have been located had it not been interrupted by the opening.

Mike Guertin and Rick Arnold are professional builders in Rhode Island with over 20 years experience building custom homes. In addition to being contributing editors for Fine Homebuilding magazine, they have written numerous articles on homebuilding, and they conduct regular seminars for builders.

Explanation:

6 0
3 years ago
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