Given:
frequency, f = 60.0 Hz
frequency, f' = 45.0 Hz
Solution:
To calculate max current in inductor, 
:
At f = 60.0 Hz
L = 0.1326 H
Now, reactance 
at f' = 45.0 Hz:
Now, is given by:
Therefore, max current in the inductor, = 2.13 A
When a person is turning onto a two-lane road divided by a broken yellow line, you know immediately that you are on a two-way road.
<h3>What is the road about?</h3>
Note that a Yellow centerlines can be seen in roads and it is one that is often used to separate traffic moving in different directions.
Note also that Broken lines can be crossed to allow slower-moving traffic and as such, When a person is turning onto a two-lane road divided by a broken yellow line, you know immediately that you are on a two-way road.
See full question below
You are turning onto a two-lane road divided by a broken yellow line. You know immediately that:
Answers
You are on a two-way road.
You are on a one-way road.
The road is under repair.
You must stay to the left of the broken yellow lines.
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Answer:
Yes, the flow is turbulent.
Explanation:
Reynolds number gives the nature of flow. If he Reynolds number is less than 2000 then the flow is laminar else turbulent.
Given:
Diameter of pipe is 10mm.
Velocity of the pipe is 1m/s.
Temperature of water is 200°C.
The kinematic viscosity at temperature 200°C is 
m2/s.
Calculation:
Step1
Expression for Reynolds number is given as follows:
Here, v is velocity, 
is kinematic viscosity, d is diameter and Re is Reynolds number.
Substitute the values in the above equation as follows:
Re=64226.07579
Thus, the Reynolds number is 64226.07579. This is greater than 2000.
Hence, the given flow is turbulent flow.
Answer:
14.506°C
Explanation:
Given data :
flow rate of water been cooled = 0.011 m^3/s
inlet temp = 30°C + 273 = 303 k
cooling medium temperature = 6°C + 273 = 279 k
flow rate of cooling medium = 0.02 m^3/s
Determine the outlet temperature
we can determine the outlet temperature by applying the relation below
Heat gained by cooling medium = Heat lost by water
= ( Mcp ( To - 6 ) = Mcp ( 30 - To )
since the properties of water and the cooling medium ( water ) is the same
= 0.02 ( To - 6 ) = 0.011 ( 30 - To )
= 1.82 ( To - 6 ) = 30 - To
hence To ( outlet temperature ) = 14.506°C
Answer:
Reduce manufacturing costs.
Explanation:
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