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wolverine [178]
3 years ago
13

I have to write the number 12.873 in words

Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0
Twelve and eight hundred seventy three thousandths
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2 Mini Lesson: A wireless phone plan costs Eric $35 for a month of service during which he sent 450 text messages. If he was cha
mafiozo [28]

9514 1404 393

Explanation:

From your knowledge of the world, you know that ...

  • the cost of multiple items is the sum of their individual costs
  • multiplication can be used for repeated addition
  • utility fees are the sum of fixed fees and usage-related fees
  • for a phone plan, text message costs are a usage-related fee

The problem statement asks for the cost of a single text message. For the purpose of finding that value, it is convenient to represent it using the variable <em>t</em>. The problem statement says Eric was billed for 450 text messages, so we expect his usage-related fee to be 450t, the sum of the costs of 450 messages--using multiplication for the repeated sum.

The problem statement says Eric was billed 12.50 for fixed fees. So, we expect Eric's total bill to be ...

  fixed fees + usage-related fees = 12.50 + 450t

The problem statement says Eric's total bill was 35.00, so we assume that is the sum of the above-listed fees. That is, the two ways to express Eric's total bill are equal.

  12.50 +450t = 35.00

4 0
3 years ago
Please can you answer this whole page please
sleet_krkn [62]

Answer:

.......................................................................................

3 0
3 years ago
Which represents the value of Point C on the number line?
postnew [5]

Answer:

no

Step-by-step explanation:

clue what this means LOLOLOL

3 0
3 years ago
Read 2 more answers
M. Score: 0 of 1 pt
beks73 [17]

Answer:

  3×5×53

Step-by-step explanation:

You can use divisibility rules to find the small prime factors.

The number ends in 5, so is divisible by 5.

  795/5 = 159

The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.

  159/3 = 53 . . . . . a prime number,* so we're done.

795 = 3×5×53

_____

* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.

5 0
3 years ago
Find the common differrence of the arithmectic sequence 6,9.4,12.8,16.2
defon
Common difference r will be the difference between next two values of number row, so we take e.g. second minus first: r=9.4-6=3.4. You can see, that this value is constant as we go through next pairs of values.
3 0
3 years ago
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