From 100 to 80 is 8/10, so the recursive formula is
an=a(n-1)*1/8
or
an= a1*1/8(n-1)
an=a1*(n-1)/8
what are the x-intercepts of the graph of the function f(x) = x2 4x – 12? (–6, 0), (2,0) (–2, –16), (0, –12) (–6, 0), (–2, –16),
joja [24]
F(x) = x^2 + 4x - 12
x-intercepts are the values of x when y = 0
x^2 + 4x - 12 = 0
(x - 2)(x + 6) = 0
x - 2 = 0 or x + 6 = 0
x = 2 or x = -6
Therefore the x-intercepts are (-6, 0), (2, 0)
Answer:
![r= [(\frac{A}{2500}) ^\frac{1}{2} -1]](https://tex.z-dn.net/?f=r%3D%20%5B%28%5Cfrac%7BA%7D%7B2500%7D%29%20%5E%5Cfrac%7B1%7D%7B2%7D%20-1%5D)
Step-by-step explanation:
Given data
Principal = $2500
time t= 2 years
Required
the rate r
Given the expression for the balance 2500(1+r)^2
Hence
![A= 2500(1+r)^2](https://tex.z-dn.net/?f=A%3D%202500%281%2Br%29%5E2)
we can make r subject of formula
![r= [(\frac{A}{P}) ^\frac{1}{t} -1]](https://tex.z-dn.net/?f=r%3D%20%5B%28%5Cfrac%7BA%7D%7BP%7D%29%20%5E%5Cfrac%7B1%7D%7Bt%7D%20-1%5D)
![r= [(\frac{A}{2500}) ^\frac{1}{2} -1]](https://tex.z-dn.net/?f=r%3D%20%5B%28%5Cfrac%7BA%7D%7B2500%7D%29%20%5E%5Cfrac%7B1%7D%7B2%7D%20-1%5D)
Hence, for any value of A, we can find the rate using the expression above