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3 years ago

How many times larger is 3x10^8 than 3x10^2

Mathematics

1 answer:

muminat3 years ago

3 0

3x10^8 is 7 times larger than 3x10^2

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All the ones in blank please

olya-2409 [2.1K]

4- 130 degrees
5-89/100

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3 years ago

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The figure is made up of 2 rectangles and 2 right triangles.

Zarrin [17]

Answer:

area = 277 units²

Step-by-step explanation:

area = (25 x 5) + (8 x 13) + (8 x 6) = 277 units²

7 0

3 years ago

2x +8=2(x + 4) what is the answer?

alexdok [17]

2x +8=2(x + 4)

mutiply the bracket by 2

(2)(x)= 2x

(2)(4)= 8

2x+8= 2x+8

move 2x to the left side

sign changes from +2x to -2x

2x-2x+8= 2x-2x+8

0+8= 0+8

8= 8

Answer:

All real numbers

4 0

3 years ago

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NEED HELP 6m²+6m-9m²

Maru [420]

6m² + 6m - 9m²

Add like terms.

(6m² - 9m²) + 6m

-3m² + 6m

~Hope I helped!~

3 0

3 years ago

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Heather left the hospital and drove toward the desert at an average speed of 35 km/h. Danielle left sometime later driving in th

elena55 [62]

Answer:

Danielle drove 3 hours

Step-by-step explanation:

Suppose Heather moved in the x direction.

Then Danielle moved in the opposite direction, that is, she moved in the -x direction.

Let's call $V_1$ , $x_1$ , $t_1$ at the speed, distance and time that I code Heather

Let's call $V_2$ , $x_2$ , $t_2$ at the speed, distance and time Danielle codes.

Observe the following diagram:

(x) Heather <------ $x_1$ --------- hospital ---------- $x_2$ -----------> Danielle (-x)

So:

$V_1 = 35\ km/h$

$t_1 = 4\ h$

$V_2 = 50\ km/h$

We know that after 4 hours the distance between Heather and Danielle was 290 km.

That is to say:

$x_2 + x_1 = 290\ km/h$

We know that $x_1= v_1t_1$

$x_1 = 35(4)$

$x_1 = 140\ km$

We already know $x_1$ , the distance from the hospital to Heather, so we can find $x_2$ and thus know $t_2$

So:

$x_2 = 290 - 140\\\\x_2 = 150\ km$

Then:

$t_2 = \frac{x_2}{v_2}\\\\t_2 = \frac{150}{50}\\\\t_2 = 3\ h$

7 0

3 years ago