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notsponge [240]
3 years ago
6

Graph 3x+y=-10 -x+3y=0

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

We have the equations in the standard form. Convert to the slope-intercept form:

3x+y=-10            <em>subtract 3x from both sides</em>

y=-3x-10

-x+3y=0             <em>add x to both sides</em>

3y=x             <em>divide both sides by 3</em>

y=\dfrac{1}{3}x

-----------------------------------------------------

We need only two points to plot a graph of each function.

y=-3x-10

for x = 0 and for x = -3:

y=-3(0)-10=0-10=-10\to(0,\ -10)\\\\y=-3(-3)-10=9-10=-1\to(-3,\ -1)

y=\dfrac{1}{3}x

for x = 0 and for x = -3:

y=\dfrac{1}{3}(0)=0\to(0,\ 0)\\\\y=\dfrac{1}{3}(-3)=-1\to(-3,\ -1)

Look at the picture.

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X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5  add x+5 to both sides
x^2-8x+15=0 now factor
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(x-5)(x-3) so x=3 and 5, using y=-x-5
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So the two solutions are:
(3,-8) and (5,-10)

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If t(n) = 15 - 2.5n, how do I find t1,t2,t3,and tn+1? I also have to express tn+1-tn in its simplest form.
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