Question

Write the equation of the circle that has a center at the origin and passes through the point (-3, -1).

Answer 1

The equation of circle with center at origin and passing through the point (-3,-1) is:

$x^2+y^2=10$

Step-by-step explanation:

The general form of equation of circle is:

$(x-h)^2+(y-k)^2=r^2$

If the center is at origin, then the equation will be:

$x^2+y^2=r^2$

Given point is: (-3,-1)

The distance of the point from origin will be the radius

The distance of any point from the origin is given by:

$r=\sqrt{x^2+y^2}\\Putting\ the\ given\ point\\r=\sqrt{(-3)^2+(-1)^2}\\r=\sqrt{9+1}\\r=\sqrt{10}$

Putting the value of r in standard equation

$x^2+y^2=(\sqrt{10})^2\\x^2+x^2=10$

The equation of circle with center at origin and passing through the point (-3,-1) is:

$x^2+y^2=10$

Keywords: Equation of circle, Radius

Learn more about equation of circle at:

• brainly.com/question/4695279
• brainly.com/question/4703807

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