Simplify this equation. 4^3·4^-6

A rectangular parking lot has a perimeter of 384 meters. The length of the parking lot is 36 meters less than the width. Find th

-Dominant- [34]

Answer:

The length and width of the parking lot is 78 meters and 114 meters respectively.

Step-by-step explanation:

Given;

Perimeter of the parking lot = $384\ m$

Solution,

Let the width of the parking lot be x.

Then, according to question length = (x-36).

The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;

$perimeter=2\times(length+width)$

Now substituting the values, we get;

$384=2\times(x-36+x)\\\frac{384}{2}=(2x-36)\\192=2x-36\\192+36=2x\\2x=228\\x=\frac{228}{2}= 114$

Width = $114\ m$

Length = $x-36=114-36=78\ m$

Hence the length and width of the parking lot is 78 meters and 114 meters respectively.

6 0

3 years ago

How do you find the normal approximation without using the continuity correction?

Dennis_Churaev [7]

Let's say you want to compute the probability $\mathbb P(a\le X\le b)$ where $X$ converges in distribution to $Y$ , and $Y$ follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing $Y$ such that its mean and variance are the same as those for $X$ .

Example: If $X$ is binomially distributed with $n=100$ and $p=0.1$ , then $X$ has mean $np=10$ and variance $np(1-p)=9$ . So you can approximate a probability in terms of $X$ with a probability in terms of $Y$ :

$\mathbb P(a\le X\le b)\approx\mathbb P(a\le Y\le b)=\mathbb P\left(\dfrac{a-10}3\le\dfrac{Y-10}3\le\dfrac{b-10}3\right)=\mathbb P(a^*\le Z\le b^*)$

where $Z$ follows the standard normal distribution.

8 0

3 years ago

F(x) = 9x^2+30x+25 pls help

lapo4ka [179]

Answer: f(x) =(3x+5)^2

x= -5/3

Step-by-step explanation:

5 0

3 years ago

At the candy store there are 420 gumdrops and 280 chocolate bars, for a total of 700 candies all together. What is the ratio of

Mekhanik [1.2K]

Answer:

5 : 2

Step-by-step explanation:

Given that:

Number of gumdrops = 420

Number of chocolate bars = 280

Total Number of candies = 700

To find:

The ratio of candies to chocolate bars = ?

Solution:

First of all, let us discuss the method to find the ratio of any two quantities.

Suppose, we need to find the ratio of two numbers $p$ and $q$ .

Then to find the ratio $p:q$ , we need to divide p by q and represent it in the simplest form $\frac{a}{b}$ such that a and b can not be divided further.

Here, to find the ratio of candies to chocolate bar:

$Ratio = \dfrac{\text{Number of candies}}{\text{Number of chocolate bars}}\\\Rightarrow \dfrac{700}{280}$

Here, we can simplify the fraction by dividing the numerator and denominator by 10 first:

$\dfrac{70}{28}$

Now, let us divide the numerator and denominator by 14:

$\dfrac{5}{2}$

So, the ratio is <em>5 : 2</em>

6 0

3 years ago

In her free time, isabelle likes to read. she kept track of the number of pages in each book she read last summer. this box plot

Free_Kalibri [48]

200 is the median (50%) of the data represented in the box plot. The fraction of the books has 200 or fewer pages is: 1/2.

<h3>What is the Median of a Data in a Box Plot?</h3>

In a box plot, the median is indicated as the value marked by the vertical line that divides the rectangular box of the box plot.

The median is the middle of the data and represents the 50th percentile. That is 1/2 the data.

In the box plot given, 200 pages is the median. Therefore, the fraction of the books that have 200 or fewer pages is: 1/2.

Learn more about box plot on:

brainly.com/question/14277132

#SPJ1

8 0

2 years ago