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3 years ago

Which of the following is a linear function?

Mathematics

1 answer:

FrozenT [24]3 years ago

4 0

Just look up a linear calculator.

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15 is 60% of what number?

Mazyrski [523]

15 is 60% of 25. 15/25 is equal to .6 or 60%

8 0

2 years ago

Read 2 more answers

Find the surface area of this net.

Elden [556K]

Answer:

Step-by-step explanation:

First, let's find the surface area of both the triangles

5x3=15

So, the surface area of the triangles is 15 sq.cm

Now, let's find the surface area of the base (large rectangle in the middle)

12x8=?

10x8=80

2x8=16

80+16=96

12x8=96

So, the surface area of the base, is 96sq.cm

Now, let's find the surface area of both of the side rectangles

12x5=60

60x2=120

So, the surface area of the two side rectangles is 120sq.cm

Now, let's find the total surface area by adding all of our answers.

120+96=216

216+15=231

<h2>So hence, the surface area of this net is 231cm²</h2>

3 0

2 years ago

Which function below is the inverse of f(x) = x^2-9

USPshnik [31]

To find the inverse
replace f(x) with y
switch all x and y
solve for y
replace y with f⁻¹(x)

f(x)=x^2-9
y=x^2-9
x=y^2-9
x+9=y^2
sqrt both sides
$\sqrt{x+9}$
replace
f⁻¹(x)= $\sqrt{x+9}$

that is the inverse

5 0

3 years ago

Decrease<br> M720.00 by 25%

netineya [11]

Answer:

540

Step-by-step explanation:

720 (100-25) to find the decimal to use (below 1.00 is decreasing)

720 (.75) = 540

8 0

3 years ago

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

2 years ago