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3 years ago

The wholesale cost of a bicycle is $98.75.

Mathematics

1 answer:

mixer [17]3 years ago

8 0

Answer:

$131.60

Step-by-step explanation:

For the promotion, markup is 33.3% of the selling price.

Now, Selling Price = Cost price + Cost price*Markup

Selling Price = $98.75 + $98.75*33.3%

Selling Price = $98.75 + $32.88375

Selling Price = $131.63375

Selling Price = $131.60

Thus, the selling price of the bicycle after calculating the markup is $131.60.

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Trudy's Trinkets is having its annual summer sale, when every item in the store gets marked

jekas [21]

Answer:

$17

Step-by-step explanation:

Sale price of 1 bracelet:

36/3

$12

sale is $5 less than original.

12+5

$17

7 0

3 years ago

ABCD is a trapezium with AB= x cm, DC=( x+ 4 )cm and the distance between the parallel sides AB and DC is 1/2 x cm

horsena [70]

We know that the smaller base is x cm, the greater base is x+4 cm, and that the height is x/2 cm.

Since the area of a trapezium is given by

$A=\dfrac{(b+B)h}{2}$

If we plug the expressions we have

$A=\dfrac{(x+(x+4))\frac{x}{2}}{2}=\dfrac{(2x+4)x}{4}=\dfrac{2x^2+4x}{4}$

If this must equal 84, we can solve for x as follows: start with

$\dfrac{2x^2+4x}{4}=84$

Multiply both sides by 4:

$2x^2+4x=336$

Subtract 336 from both sides:

$2x^2+4x-336=0$

We can divide both sides by 2 to make computation simpler:

$x^2+2x-168=0$

Use the quadratic formula (or any mean you prefer) to solve this equation and get the solutions

$x_1=-14,\quad x_2=12$

We can't accept the negative solution, because it would imply

$AB=-14,\quad CD=-10$

and we can't have negative side lengths. So, the answer is 12.

4 0

3 years ago

What does this fraction show or model what’s the answer I need help

Minchanka [31]

Answer:

I belive that the answer is D because there is 2 items and if u count the different colors by 1 it would be 6

7 0

3 years ago

A function has a slope of 3, and one solution is given in the table. Identify the missing outputs.

sergejj [24]

Answer:

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5 0

3 years ago

In the diagram below of triangle UVW, X is a midpoint of UV and Y is a midpoint

NeTakaya

Step-by-step explanation:

Given: X is midpoint of UV and Y is midpoint of VW.

$\therefore XY || UW$

(By mid-point theorem)

$\therefore \angle XYV \cong \angle UWY\\.. (corresponding\: \angle 's) \\\therefore m\angle XYV = m\angle UWY\\\therefore 98 - 6x = 63- x\\\therefore 98 - 63= 6x- x\\\therefore 35= 5x\\\\\therefore x = \frac{35}{5}\\\\\huge \orange {\boxed {\therefore x = 7}} \\\\m\angle UWY = (63 - x) °\\\\\therefore m\angle UWY = (63 - 7) °\\\\\huge \purple {\boxed {\therefore m\angle UWY = 56 °}}$

5 0

3 years ago