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brilliants [131]
3 years ago
12

We know that 455 students are in school today.

Mathematics
1 answer:
EastWind [94]3 years ago
4 0

Answer:

650

Step-by-step explanation:

s= 455/0.70

s=650

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On a test Denzel answers that 3x + 6a + 7 is equivalent to 3(x + 2a +7). Is Denzel correct, why or why not? * Yes, he is correct
emmainna [20.7K]

Answer:

No, he is not correct because the constant in his answer should have been 21 not 7.

Step-by-step explanation:

3(x+2a+7)=3x+6a+21

Therefore, the correct answer is the fourth; he should have put 21.

6 0
3 years ago
Write the function of this graph​
Colt1911 [192]

Answer:

f(x) = -3/7x - 6

Step-by-step explanation:

5 0
3 years ago
Emmett gathered some data to compare the monthly cost of renting a one-bedroom apartment in Dallas and Austin. The data collecte
Goryan [66]

Answer:

The correct options are;

a) The city's data has the higher median monthly apartment cost of the two cities by $155

b) The city's data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data

Step-by-step explanation:

The given data for the cost of renting a one-bedroom apartment in Dallas is presented as follows;

$994, $1,322, $1,075, $1,189, $1,172, $1,465, $1,215, $930, $1,090, $1,288

Which can be arranged in increasing order and analyzed to find the interquartile range, mean and standard deviation using Microsoft Excel as follows;

$930, $994, $1,075, $1,090, $1,172, $1,189, $1,215, $1,288, $1,322, and $ 1,465

The first quartile, Q₁ = $1,054.75

The third quartile, Q₃ = $1,296.5

The interquartile range = Q₃ - Q₁ = $241.75

The median = $1,180.5

The average monthly cost = $1,174

The standard deviation of the sample = $159.9597

The given data for the cost of renting a one-bedroom apartment in Austin is presented in increasing order using Microsoft Excel as follows;

$900, $950, $1,100, $1,250, $1,296, $1,375, $1,389, $1,400, $1,450, $1,495

The interquartile range, mean and standard deviation are found using Microsoft Excel as follows;

The first quartile, Q₁ = $1,062.5

The third quartile, Q₃ = $1,412.5

The interquartile range = Q₃ - Q₁ = $1,412.5 - $1,062.5 = $350

The median = $1,335.5

The average monthly cost = $1,260.5

The standard deviation of the sample = $209.0945

The difference in the median cost of the two cities is $1,335.5 - $1,180.5 = $155

Therefore, the Austin's city data has the higher median monthly apartment cost of the two cities by $155

b) The difference in the sample standard deviation of the two cities is $209.0945 - $159.9597 = $49.13476

Therefore, the Austin city data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data.

7 0
3 years ago
Read 2 more answers
Describe how you would use the rules of exponents to simplify (7x?yz) 3. You may indicate an exponent in your answer with ^. For
SVETLANKA909090 [29]

Answer:

343x^6y^3z^3

Step-by-step explanation:

One of the rules of exponents demands:

(abc)^m=a^mb^mc^m

where a, b, c and m are coefficients.

Furthermore, you use the following rule for exponents of variables that already have an exponent:

(a^n)^m=a^{m*n}

Thus, you can apply this rules in the following way:

(7x^2yz)^3=(7)^3(x^2)^3(y)^3(z)^3=7*7*7x^{2*3}y^3z^3=343x^6y^3z^3

hence, the answer is 343x^6y^3z^3

5 0
3 years ago
A bicycle training wheel has a radius of 3 inches. The bicycle wheel has a radius of 10 inches. Approximately how much smaller,
zhuklara [117]

Answer:

285.74\text{ inch}^2

Step-by-step explanation:

GIVEN: A bicycle training wheel has a radius of 3\text{ inch}. The bicycle wheel has a radius of 10\text{ inch}.

TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.

SOLUTION:

radius of bicycle wheel =10\text{ inch}

area of bicycle wheel =\pi r^2

putting value,

area of bicycle wheel =3.14\times10^2

                                    =314\text{ inch}^2

radius of bicycle training wheel =3\text{ inch}

area of bicycle training wheel =\pi r^2

putting value,

area of bicycle wheel =3.14\times3^2

                                    =28.26\text{ inch}^2

difference in area of bicycle wheel and bicycle training wheel

=\text{area of bicycle wheel}-\text{area of bicycle training wheel}

=314-28.26

=285.74\text{ inch}^2

hence the training wheel is 285.74\text{ inch}^2 smaller than regular wheel

4 0
3 years ago
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