All categories

3 years ago

A body is pulled along a horizontal force of 20N calculate the work done in moving a distance of 40m

Physics

1 answer:

andrew-mc [135]3 years ago

6 0

Answer:

<h3>The answer is 800 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

From the question

force = 20 N

distance = 40 m

We have

work done = 20 × 40

We have the final answer as

Hope this helps you

You might be interested in

*brainlest* An object accelerates from rest with a constant acceleration of 2m/s^2. How far will it have moved after 9s? Equatio

boyakko [2]

Answer: You throw an object upwards from the ground with a velocity of 20m/s and it is subject to a downward

acceleration of 9.8 m/s2. How high does it go?

Given Formula Set up Solution

vi=20 m/s

vf=0 m/s

a=-9.8 m/s2

x=?

2 = vi

2 + 2a x (0 m/s)2= (20 m/s)2 + 2 (-

9.8 m/s2) x

x=20.4 meters

Explanation: i known/ i hoped that helped.

6 0

3 years ago

(Part 1 of 3)

Ksju [112]

1) $1.028 m/s^2$

We can solve this part by using Newton's second law:

$F=ma$ (1)

where

F is the net force

m is the mass

a is the acceleration

There are two forces acting on the boat:

$F_1= 2.90 \cdot 10^3 N$ forward

$F_2 = 1.69\cdot 10^3 N$ backward

So the net force is

$F=2.90\cdot 10^3-1.69\cdot 10^3=1.21\cdot 10^3 N$

We know that the mass of the boat is

m = 1177.5 kg

So we can now use eq.(1) to find the acceleration:

$a=\frac{F}{m}=\frac{1.21\cdot 10^3}{1177.5}=1.028 m/s^2$

2) 161.0 m

We can solve this part by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance travelled

u is the initial velocity

t is the time

a is the acceleration

Here we have

u = 0 (the boat starts from rest)

$a=1.028 m/s^2$

Substituting t = 17.7 s, we find the distance covered:

$s=0+\frac{1}{2}(1.028)(17.7)^2=161.0 m$

3) 18.2 m/s

The speed of the boat can be found with the following suvat equation

$v=u+at$

where

v is the final velocity

u is the initial velocity

t is the time

a is the acceleration

In this case we have

u = 0 (the boat starts from rest)

$a=1.028 m/s^2$

And substituting t = 17.7 s, we find the final velocity:

$v=0+(1.028)(17.7)=18.2 m/s$

And the speed is just the magnitude of the velocity, so 18.2 m/s.

6 0

4 years ago

Addition of _____________ to pure water causes the least increase in conductivity.

Mademuasel [1]

Answer:

salt

Explanation:

5 0

3 years ago

Can someone please help me with a physics assignment on Friday?

zalisa [80]

Yes what do you need help on

6 0

3 years ago

Read 2 more answers

Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each ot

jolli1 [7]

Answer:

The electric force between them if the pieces of grain are 2 cm apart is $3.15\times 10^{-11}\textrm{ N}$ .

Explanation:

Given:

Charge on one grain, $Q_{1}=6\times 10^{-10}\textrm{ C}$

Charge on another grain, $Q_{2}=2.3\times 10^{-15}\textrm{ C}$

Separation between them, $d=2\textrm{ cm}=0.02\textrm{ m}$

Electric force acting between two charges $Q_{1}\textrm{ and }Q_{2}$ separated by a distance $d$ is given as:

$F_{elec}=\frac{kQ_{1}Q_{2}}{d^2}$

Where, $k$ is Coulomb's constant equal to $9\times 10^9\textrm{ }Nm^2/C^2$ .

Now, plug in all the values and solve for $F{elec}$ .

$F{elec}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}$

Therefore, the electric force between them if the pieces of grain are 2 cm apart is $3.15\times 10^{-11}\textrm{ N}$ .

3 0

3 years ago