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3 years ago

What is the spring potential energy of a spring that is stretched 15 cm if its spring constant is 350 n/m?

Physics

1 answer:

VladimirAG [237]3 years ago

6 0

Answer:

Spring potential energy = 7.875Nm

Explanation:

Given the following data;

Extension, e = 15cm to meters = 15/100 = 0.15m

Spring constant, k = 350n/m

To find the force;

Force = spring constant * extension

Force = 350 * 0.15

Force = 52.5 Newton.

Now to find the spring potential energy we would use the formula below;

Spring potential energy = force * extension

Substituting into the equation, we have;

Spring potential energy = 52.5 * 0.15

Spring potential energy = 7.875Nm

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Forces that are equal in strength and opposite indirection are

Otrada [13]

Hey there! My name is Christy and I'm gladly to help you out!

The three main forces that stop moving objects are friction, gravity and wind resistance. Equal forces acting inopposite directions are called balanced forces. Balanced forcesacting on an object will not change the object's motion. When you add equal forces in opposite direction, the netforce is zero.

Hope this helped!

4 0

3 years ago

Read 2 more answers

Which of the following choices is a single-replacement reaction? A. 2K + Br2 2KBr B. 2H2 + O2 2H2O C. Mg + FeO Fe + MgO D. C + 2

Otrada [13]

A single replacement reaction occurs when two different cations switch places to combine with the same anion. One element forms a compound while another element is released from the compound. In a single replacement reaction, or single displacement reaction, a single uncombined element replaces another in a compound.

So you're answer is probably c.

5 0

3 years ago

Use the equation of motion to answer the question. Use the equation of motion to answer the question.

satela [25.4K]

The final position of the object after 2 s is 11 m.

Motion: This can be defined as the change in position of a body.

⇒ Formula:

x = x₀+v₀t+1/2(at²)........................ Equation 1

⇒ Where:

x = Final position of the object
x₀ = Starting position
v₀ = Starting velocity
t = time
a = acceleration

From the question,

⇒ Given:

x₀ = 4.5 m/s
t = 2 s
x₀ = 2m
a = 0 m/s²

⇒ Substitute these values into equation 1

x = 2+(4.5×2)+1/2(0²×2)
x = 2+9+0
x = 11 m

Hence, The final position of the object after 2 s is 11 m

Learn more about motion here: brainly.com/question/15531840

4 0

2 years ago

For an increase in the bulk modulus of a material but without any change in the density, what happens to the speed of sound in t

vazorg [7]

The speed of sound, c, is given by the Newton-Laplace formula
$c = \sqrt{ \frac{K}{\rho} }$
where
K = bulk modulus
ρ = density

Because the density is constant, the speed of sound is proportional to the square root of the bulk modulus.

Therefore when the bulk modulus increases, the speed of sound increases by the square root of the bulk modulus.

For example, if K is doubled, then
$c = \sqrt{2K} = \sqrt{2} \sqrt{K}$

Answer:
If the bulk modulus increases by a factor of n, then c increases by a factor of √n.

7 0

3 years ago

A man claims that he can hold onto a 15.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man

suter [353]

Answer:

F= 5195.625 N

Explanation:

To obtain the force needed to hold the child, we need to know the aceleration in which the car is breaking.

Aceleration is equal to velocity divided by the time of breaking

In international system, velocity [m/s] is

v= (62 mi/h)*(1609 m/mi)*(1 h/3600 s)

v= 27.71 m/s

Now, we part the velocity by the time that is 0.08 seconds

a= v/t= (27.71 m/s)/(0.08 s)

a= 346.375 m/ $s^{2}$

The force in agreement with the Newton's second law is

F=m*a = 15 Kg*346.375 m/ $s^{2}$

F= 5195.625 N

(Note: 1 N = 1 Kg*m/ $s^{2}$ )

3 0

3 years ago