Answer:
no, because for x=-3, y would have to be -31
Step-by-step explanation:
boy oh boy (or girl oh girl) - you wrote this in a horrible, horrible format.
I can only guess what your problem and the fitting answer would be.
y = -2×x^2 + 3×x - 4
-4 = -2×(-3)^2 + 3×(-3) - 4
-4 = -2×9 - 9 - 4
-4 = -18 - 9 - 4
-4 = -31
and that is wrong. for (-3,-4) to be on the graph of the function, y would have to be -4 when using x=-3 in the function. but y = -31 for x= -3.
Answer:
-2
Step-by-step explanation:
Start with the vertex form of the equation of a parabola: y - k = a(x - h)^2
Here h = -2, k = -3, x = -1, y = -5. Find a:
-5 - [-3] = a(-1 - [-2])^2, or
-5 + 3 = a(1)^2, or
-2 = a
The unknown coefficient is -2.
To find c, you must isolate it.
To do this, you must divide both sides by 5/7, since that is being multiplied by c and you must do the inverse to it to cancel it out in order to leave c by itself.
5/7c ÷ 5/7 = c
13/14 ÷ 5/7
To divide fractions, follow these steps:
Step 1- Turn the second fraction, 5/7 in this case, into its reciprocal. This means swapping the places of the numerator and denominator.
5/7 reciprocal = 7/5
Step 2- multiply the original first fraction and reciprocal second fraction.
13/14 • 7/5
13 • 7 = 91
14 • 5 = 70
13/14 ÷ 5/7 = 91/70
Step 3- Simplify if possible.
91/70
Since 70 can go into 90, you can turn this into a mixed number.
1 and 21/70
Now simplify 21/70.
Both can be divided by 7.
21 ÷ 7 = 3
70 ÷ 7 = 10
So simplified, 91/70 equals 1 and 3/10.
As a decimal, this is 1.3.
So the answer is c = 1.3, or 1 and 3/10.
Hope this helps :)
We have to add 3 2/3 + 2 2/3 using fraction strips. 3 2/3 and 2 2/3 are the mixed numbers. The mixed numbers consists of a whole number and a fraction. If we want to add those numbers we shoukld change them into improper fractions: 3 2/3 = ( 3 * 3 + 2 ) / 3 = 11 / 3; 2 2/3 = ( 2 * 3 + 2 ) / 2 = 8 / 3. Finally: 11 / 3 + 8 / 3 = ( 11 + 8 ) / 3 = 20 / 3 = 6 2/3. Answer: You reneme it turning them into improper fractions<span>. </span>
