3 years ago

Simplify (2b^3+b^2)+(3b^3+b^4)

Mathematics

1 answer:

RideAnS [48]3 years ago

3 0

(2b^3+b^2)+(3b^3+b^4)

b^4 +2b^3 + 3b^3 +b^2

b^4 +5b^3 +b^2

You might be interested in

The diameter of Jen’s bicycle tire is 30cm. About how many revolutions will her tire make in a 20,000 cm journey?( Use pi =3.14

Verdich [7]

Answer:

213

Step-by-step explanation:

The circumference of the wheel is given by

C=2πr=πd

Where d is diameter, r is radius and c is circumference

The number of revolutions N multiplied by circumference should yield the total distance

N*πd= Distance

Given distance of 20, 000 cm and diameter of 30 cm

30πN=20000

Making N the subject of formula

N=20000/(30π)=212.20659078919378102517835116335248271261

Rounded off, about 213 revolutions are required

3 0

3 years ago

Which number should be added to the expression x^2-8x to change it into a perfect square trinomial?

vovangra [49]

The perfect square $(x-a)^2$ can be expanded as follows:

$(x-a)^2=x^2-2ax+a^2$

So, we have to think of the term $-8x$ as $-2ax$ , which implies $a=4$ .

Thus, we have to add $a^2$ , i.e. 16, to complete the perfect square:

$(x-4)^2 = x^2-8x+16$

3 0

3 years ago

Two health clubs offer different pricing plans for their members. Both health clubs charge a one-time sign-up fee and a monthly

Rainbow [258]

Answer:

y = (constant variable x time) + independent variable

y = 60x + 30 ← Health Club B

y = 27x + 50 ← Health Club A

Step-by-step explanation:

I can't see the question at the bottom due to the covering but if you comment I can edit this and give a proper answer. Otherwise this is all I can give you.

6 0

1 year ago

What is this math question -22a =462

Lerok [7]

Answer:

a = -21

Step-by-step explanation:

-22 x -21 = 462

6 0

3 years ago

Calculate the slope of the line that passes through the points (-4,-7) and (1,-7)

uranmaximum [27]

$\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-7}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-7}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-4)}}}\implies \cfrac{-7+7}{1+4}\implies \cfrac{0}{5}\implies 0$

8 0

4 years ago

Read 2 more answers