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hram777 [196]
3 years ago
8

Aiden and his sister saved 360 quarter altogether. Aiden saved twice as many quarters as his sister, If Aiden plans to put his q

uarter into 3 equal piles, how many quarters will he put in each pil.
Mathematics
1 answer:
IgorC [24]3 years ago
5 0

Answer:

Aiden and his sister have 360 quarters together. If Aiden has twice as much as his sister, he has 180 quarters.

360/2 = 180

Aiden divides his quarters into 3 equal piles.

180/3 = 60

Aiden has 60 quarters in each of his 3 piles.

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U
elena55 [62]

Answer:

option 3, 45

Step-by-step explanation:

3x - 9° + 30° + 24° = 180° (angle sum property of a triangle)

3x - 9° + 54° = 180°

3x + 45° = 180°

3x = 180° - 45°

3x = 135°

x = 135/3

x = 45°

therefore, option 3 is the correct option

8 0
3 years ago
A farmer has both pigs and chickens on his farm there are 78 fee and 27 heads how many pigs and how many chickens are there
Andre45 [30]
Assuming health non-mutated animals:
Feet = 4*Pigs + 2*Chickens
Heads = Pigs + Chickens

By back substitution:
78 = 4*(27-Chickens) + 2*Chickens
78 = 108 -2*Chickens
-30 = -2*Chickens
Chickens= 15

Then:
27 = Pigs + 15
Pigs = 12

To check:
Feet = 4*Pigs + 2*Chickens
78 = 4*12 + 2*15
78 = 48 + 30
78 = 78 CHECKS
6 0
3 years ago
12 for charity walk 3 miles how much did his cousin pay per mile
WITCHER [35]
His cousin paid 4 per mile. You have to find the unit rate and you find that by dividing 12 by 3 which gives you 4. 
8 0
3 years ago
Read 2 more answers
Find the half range Fourier sine series of the function
worty [1.4K]
The full range is -\pi (length 2L=2\pi), so the half range is L=\pi. The half range sine series would then be given by

f(x)=\displaystyle\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L=\sum_{n\ge1}b_n\sin nx

where

b_n=\displaystyle\frac2L\int_0^Lf(x)\sin\dfrac{n\pi x}L\,\mathrm dx=\frac2\pi\int_0^\pi(\pi-x)\sin nx\,\mathrm dx

Essentially, this is the same as finding the Fourier series for the function

\begin{cases}g(x)=\begin{cases}\pi-x&\text{for }0

Integrating by parts yields

b_n=\dfrac2\pi\left(\dfrac\pi n-\dfrac{\sin n\pi}{n^2}\right)=\dfrac2n

So the half range sine series for this function is simply

f(x)=\displaystyle\sum_{n\ge1}\frac{2\sin nx}n
5 0
3 years ago
6.) (-2)4 + (-10) ÷ (-3 + -1 + -1)
Licemer1 [7]

Step-by-step explanation:

  1. (-2)4 = -8
  2. -8 +(-10)= -18
  3. -18 divide by -5= 18/5
7 0
3 years ago
Read 2 more answers
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