Answer:
<h3>#1</h3>
<u>The system of equations:</u>
- 2x + 7y = -11
- 3x + 5y = -22
Solve by elimination.
<u>Triple the first equation, double the second one, subtract the second from the first and solve for y:</u>
- 3(2x + 7y) - 2(3x + 5y) = 3(-11) - 2(-22)
- 6x + 21y - 6x - 10y = -33 + 44
- 11y = 11
- y = 1
<u>Find x:</u>
- 2x + 7*1 = -11
- 2x = -11 - 7
- 2x = -18
- x = -9
<u>The solution is:</u>
<h3>#2</h3>
<u>Simplifying in steps:</u>
- 8u - 29 > -3(3 - 4u)
- 8u - 29 > - 9 + 12u
- 12u - 8u < -29 + 9
- 4u < -20
- u < -5
Answer:
f(10) = 13
Step-by-step explanation:
f(x) = x/2 + 8
Let x = 10
f(10) = 10/2 +8
f(10) = 5+8
f(10) = 13
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
Therefore
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
( using the property
)
( using the property 
( combining the like powers )
( using the property
)

( using the property
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
I=prt.....
i=5000*10*0.03=1500
5000+1500=6500