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kondaur [170]
3 years ago
12

Brittany's mom gave her $15.00 to buy school supplies. Brittany needs to buy 3 notebooks and some mechanical pencils. If each no

tebook costs $2.99 and each mechanical pencil costs $1.50, how many mechanical pencils can Brittany buy using only the money her mom gave her?
Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

Answer:

4 mechanical pencils

Step-by-step explanation:

Each notebook is worth $2.99

So buying 3 of the notebooks would leave her with $8.97

Then, $15.00 - $8.97= $6.05

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Plz help me 75 points for the 2 questions!!!
liraira [26]

Answer:

<h3>#1</h3>

<u>The system of equations:</u>

  • 2x + 7y = -11
  • 3x + 5y = -22

Solve by elimination.

<u>Triple the first equation, double the second one, subtract the second from the first and solve for y:</u>

  • 3(2x + 7y) - 2(3x + 5y) = 3(-11) - 2(-22)
  • 6x + 21y - 6x - 10y = -33 + 44
  • 11y = 11
  • y = 1

<u>Find x:</u>

  • 2x + 7*1 = -11
  • 2x = -11 - 7
  • 2x = -18
  • x = -9

<u>The solution is:</u>

  • x = -9, y = 1
<h3>#2</h3>

<u>Simplifying in steps:</u>

  • 8u - 29 > -3(3 - 4u)
  • 8u - 29 > - 9 + 12u
  • 12u - 8u < -29 + 9
  • 4u < -20
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3 0
3 years ago
If f(x) = x over 2 + 8, what is f(x) when x = 10?
jeka57 [31]

Answer:

f(10) = 13

Step-by-step explanation:

f(x) = x/2 + 8

Let x = 10

f(10) = 10/2 +8

f(10) = 5+8

f(10) = 13

8 0
3 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
Read 2 more answers
If you invest $5000 in an account 10 years at a 3% interest rate, how much money will you have?
Tanya [424]
I=prt..... i=5000*10*0.03=1500 5000+1500=6500
7 0
3 years ago
3a. State whether the following is true or false. *
olganol [36]

Answer:

The answer is False

7 0
3 years ago
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