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4 years ago

What is the answer and why is it true?

Mathematics

2 answers:

Ad libitum [116K]4 years ago

8 0

Answer:

Step-by-step explanation:

1.5+1.5=3

ghe other side is 3 pounds therefore balanced

pashok25 [27]4 years ago

7 0

Answer:

1.5 lbs b/c 2 block equal 3 vs 3 blocks equal 3

Step-by-step explanation:

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One of the legs of a right triangle measures 15 cm and its hypotenuse measures 17 cm. Find the measure of the other leg. If nece

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Step-by-step explanation:

The Pythagorean theorem shows us that the measure of the sides in a right triangle can be calculated using the formula a^2 + b^2 = c^2. Using this formula, and filling in the blank, we can conclude that the other leg measures 8 cm.

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3 years ago

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Hannah paid $8.63 at the grocery store for beans and potatoes. She bought 4 pounds of beans at $0.62 per pound and 5 pounds of p

irina [24]

Answer:

$1.23

Step-by-step explanation:

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3 years ago

3) The two largest oil spills together released 298 million gallons of oil into the oceans. The smaller of the two released 58

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Step-by-step explanation:

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4 years ago

In a ∆ABC , angle A + Angle B = 125° and Angle B + Angle C = 150° . Find all the angles of ∆ABC.

mel-nik [20]

$\large\underline{\sf{Solution-}}$

Given that,

<em>In triangle ABC</em>

$\purple{\rm :\longmapsto\:\angle A + \angle B = 125 \degree \: - - - (1) }$

$\purple{\rm :\longmapsto\:\angle B + \angle C = 150 \degree \: - - - (2)}$

We know,

Sum of all interior angles of a triangle is supplementary.

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C = 180\degree }$

<u>On adding equation (1) and (2), we get </u>

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle B + \angle C = 125\degree + 150 \degree \:}$

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C + \angle B = 275\degree \:}$

$\purple{\rm :\longmapsto\:180\degree + \angle B = 275\degree \:}$

$\purple{\rm :\longmapsto\:\angle B = 275\degree - 180\degree \:}$

$\purple{\rm :\longmapsto\:\angle B = 95\degree \:}$

On substituting the value in equation (1) and (2), we get

$\purple{\rm :\longmapsto\:\angle A + 95\degree = 125\degree }$

$\purple{\rm :\longmapsto\:\angle A = 125\degree - 95\degree }$

$\purple{\rm :\longmapsto\:\angle A = 30\degree }$

Also, from equation (2), we get

$\purple{\rm :\longmapsto\:95\degree + \angle C = 150\degree }$

$\purple{\rm :\longmapsto\:\angle C = 150\degree - 95\degree }$

$\purple{\rm :\longmapsto\:\angle C = 55\degree }$

Hence,

$\begin{gathered}\begin{gathered}\bf\: \rm\implies \:\begin{cases} &\sf{\angle A = 30\degree } \\ \\ &\sf{\angle B = 95\degree } \\ \\ &\sf{\angle C = 55\degree } \end{cases}\end{gathered}\end{gathered}$