Answer:
y = -20x + 100
Step-by-step explanation:
As per your requirement For Part B, the solution is
The equation in slope-intercept form to model the relations is below:-
To reach 2 points on the graph the line passes through
lets use p1(0, 100), p2(1, 80)
now we will compute the slope:


= -20
and now use line equation in form point-slope:
y - y1 = m(x - x1)
y - 100 = -20(x - 0)
y = -20x + 100
Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
Greater than
1/6 x 3/2 = 1/4
1/4 > 1/6
In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC and AB have any negative reciprocals.Lets find the slopes .
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1
Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle
Answer:
2.8a²+0.9a - 1.2
Step-by-step explanation:
Given the expression 0.3(3a-4)-0.05(8a)(-7a)
Expand using the distributive law
0.3(3a-4)-0.05(8a)(-7a)
0.3(3a)-0.3(4)-0.05(8a)(-7a)
0.9a-1.2 - 0.05(8a)(-7a)
0.9a - 1.2 + 2.8a²
Rearrange
2.8a²+0.9a - 1.2
Hence the required expression is 2.8a²+0.9a - 1.2