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Katen [24]
3 years ago
5

Help I need answers fast Thank you for the help

Biology
1 answer:
Reptile [31]3 years ago
5 0

the stomach is c, the appendix is d, the rectum is b, and the duodenum is a

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What is the sample variance of the following data, which describe the height growth of 10 foxtal pine trees grown in a common ga
maksim [4K]

Answer:

Although the data in the question is not clearly stated, the correct date is stated in the image attached to this answer and it is also stated below

What is the sample variance of the following data, which describe the height growth of 10 foxtail pine trees grown in a common garden ( give your  answer to one decimal place)?

Tree            Height(cm)

1                  25.6987

2                 19.6587

3                 11.4780

4                 9.11130

5                 16.8747

6                 14.7771

7                 33.0001

8                 24.0000

9                 19.4441

10                14.1010

answer 51.9

Explanation:

what is a sample variance?

A sample variance (denoted as S^{2}) is used to calculate how far a set of numbers are from the mean value of the set. Mathematically, it is defined as the average of the squared deviations from its mean value.

Let the individual value of the trees be represented as x₁ to x₁₀

Let the total number of Foxtail pine trees be N

To calculate the standard deviation, we will first calculate the mean or average of the height of the trees

1. Mean (μ) = \frac{x_{1}+x_{2}+x_{3}+x_{4}+x_{5}+x_{6}+x_{7}+x_{8}+x_{9}+x_{10}  }{N}

                  = \frac{25.6987+19.6587+11.4780+9.11130+16.8747+14.7771+33.0001+24.0000+19.4441+14.1010}{10}  = \frac{188.1437}{10} = 18.8144

2. we need to calculate the sum of the squares of the individual deviations.

∑[x-μ]²= (25.6987-18.8144)^{2}+(19.6587-18.8144)^{2}+(11.4780-18.8144)^{2}+(9.11130-18.8144)^{2}+(16.8747-18.8144)^{2}+(14.7771-18.8144)^{2}+(33.0001-18.8144)^{2}+(24.0000-18.8144)^{2}+(19.4441-18.8144)^{2}+(14.1010-18.8144)^{2}=466.8786

3. Now the variance is ; (∑[x-μ]²) ÷ (N-1) and since N=10, then N-1 = 10-1 = 9

= \frac{466.8786}{9} = 51.8754.

we were asked the give our answer to one decimal place

∴ Variance(S^{2})= 51.9

   

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How do the positions of the aronium and antheridium relate to their reproductive function?
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Answer:

Generally in non flowering plant the male sex organ is called the antheridium,while the female is called the  achegonium. Due to the habitat and methods of reproduction, special adaptive feature s have been developed by these plants to ensure reproduction and prevent extinction.

Explanation:

Based on structure,Antheridial (male sex cells) are usually upright in position,with pores located at the top of the antherialdial disk.These perforation is adaptive feature for effective dispersal of sperm during reproduction.

In addition  present in the  archegoniu is  the achegonium dsik. The latter  is the adaptive feature for protection of the archegonia.The disc serve as an umbrella surface for the protection of the archegonia during reproduction.Thus ovum is well protected  to ensure fertilization and prevent wastage.

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Correct answer - potometer.

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