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2 years ago

Is y = 0 the asymptote of all functions of the form f(x) = ab^x? Explain your reasoning.

1 answer:

6 0

Y=0 would be a horizontal line. An asymptote is a line that a function approaches, but never reaches. Exponential functions such as these are a smooth curve. If both numbers are positive numbers greater than or equal to 1, the curve increases. If at least one of the numbers is a positive number between 0 and 1, the curve decreases. If a is a negative number, the curve decreases as well. If either a or b is zero, then the graph would stay constant at 0. However, as long as neither a nor b is zero, then this graph will never touch that point. The only way to get an answer of y=0 is to multiply by 0. If neither a nor b is zero, this won't happen.

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PLEASE HELP! Let f(x)= 6x+1 find f(a) + f(2)

SpyIntel [72]

Answer:

6(a)+14

Step-by-step explanation:

First you need to find f(a) and f(2) separately, then add them together after

f(a) = 6(a)+1

f(2) = 6(2)+1 = 12+1 = 13

so f(a)+f(2) = 6(a)+1+13 = 6(a)+14

6 0

2 years ago

The width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of

zzz [600]

Answer:

I think you should pick 35

5 0

3 years ago

A circular fish pond is shown below. What is the circumference of the pond? The radius is 18.5cm

alisha [4.7K]

Answer:

about 116.18

Step-by-step explanation:

Circumference is 2PI*radius

So it should equal 37*3.14 which equals about 116.18

7 0

2 years ago

Simplify the expression. -5+i/2i

Lostsunrise [7]

Answer:

$\rm - \dfrac{11}{2}$

Step-by-step explanation:

$\rm Simplify \: the \: following: \\ \rm \longrightarrow - 5 + \dfrac{i}{2} i \\ \\ \rm Combine \: powers. \\ \rm \dfrac{i \times i}{2} = \dfrac{i^{1 + 1}}{2}: \\ \rm \longrightarrow - 5 + \dfrac{i^{1 + 1}}{2} \\ \\ \rm 1 + 1 = 2: \\ \rm \longrightarrow - 5 + \dfrac{i^2}{2} \\ \\ \rm i^2 = -1: \\ \rm \longrightarrow - 5 + \dfrac{( - 1)}{2} \\ \\ \rm \longrightarrow - 5 - \dfrac{1}{2} \\ \\ \rm Put \: - 5 - \dfrac{1}{2} \: over \: the \: common \: denominator \: 2. \\ \rm - 5 - \dfrac{1}{2} = \dfrac{2( - 5)}{2} - \dfrac{1}{2} : \\ \rm \longrightarrow \dfrac{ - 5 \times 2}{2} - \dfrac{1}{2} \\ \\ \rm 2 (-5) = -10: \\ \rm \longrightarrow \dfrac{ - 10}{2} - \dfrac{1}{2} \\ \\ \rm \dfrac{ - 10}{2} - \dfrac{1}{2} = \dfrac{ - 10 - 1}{2} : \\ \rm \longrightarrow \dfrac{ - 10 - 1}{2} \\ \\ \rm -10 - 1 = -11: \\ \rm \longrightarrow - \dfrac{11}{2}$

7 0

3 years ago

Which ordered pair is a solution of the equation? -3x – y = 6 Choose 1 answer:

Aleks [24]

Answer:

Step-by-step explanation:

I can not see your answers to choose but with this equation for 2 variables, you can replace the values of x and y and see if that is right or not.

For example, to know (-2,5) is a solution, you replace x= -2 and y= 5

into this equation: -3x -y = 6

and you have: -3*(-2) -5 =6

or 6-5 =6, and you find that is impossible, so (-2.5) is not a solution.

Hope you understand it

5 0

2 years ago