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Natalija [7]
3 years ago
9

Write an equation to describe the sequence below use and to represent the position of a term in the sequence where n equals one

for the first term 1, 4, 16
Mathematics
1 answer:
Katen [24]3 years ago
6 0

Answer:

  an = 4^(n-1)

Step-by-step explanation:

The three given terms have a common ratio of 4:

  4/1 = 16/4 = 4

So, this can be described by the function for a geometric sequence:

  an = a1×r^(n -1)

where an is the n-th term, a1 is the first term (1) and r is the common ratio (4).

  an = 1×4^(n-1)

  an = 4^(n -1) . . . . . simplified

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NEED HELP ASAP!<br> Subtract.<br> (4x^2+8x−2)−(2x^2−4x+3)<br>Answer in standard form
AlekseyPX
(4x^2+8x-2)-(2x^2-4x+3)\\\\=4x^2+8x-2-2x^2+4x-3\\\\=(4x^2-2x^2)+(8x+4x)+(-2-3)\\\\=\boxed{2x^2+12x-5}
4 0
3 years ago
Find the 39th term for 163, 160, 157
aniked [119]

Answer:

49

Step-by-step explanation:

delta math said it

3 0
3 years ago
Please help i am so confused
harkovskaia [24]

Answer:

q\geq -81

Step-by-step explanation:

First, begin by multiplying \frac{q}{27} \\ by its reciprocal.

To do this, flip the fraction upside-down.

The resulting equation looks like this: \frac{27}{1} *\frac{q}{27}

Cancel out the two 27's and you are left with \frac{q}{1} , which you can simplify to q.

Next, multiply -3 by \frac{27}{1} . Remember, what you do on one side, you must do on the other.

Your equation should look like this:

q\geq -81

The final answer is q\geq -81 .

Have a nice day!

3 0
3 years ago
Does anyone know how to do this and if so can you please help me and explain how to do it, it’ll be appreciated thank you
dalvyx [7]

Answer:

13) (5x)^{-\frac{5}{4} ⇒ \frac{1}{\sqrt[4]{(5x)^5}}

15) (10n)^{\frac{3}{2} ⇒ \sqrt{(10n)^3}

Step-by-step explanation:

Given expression:

13) (5x)^{-\frac{5}{4}

15) (10n)^{\frac{3}{2}

Write the expressions in radical form.

Solution:

For an expression with exponents as fraction like

(x)^{\frac{m}{n}

the numerator m represents the power it is raised to and the denominator n represents the nth root of the expression.

For an expression with exponents as negative  fraction like

(x)^{-\frac{m}{n}

We take the reciprocal of the term by rule for negative exponents.

So it is written as:

\frac{1}{(x)^{\frac{m}{n}}}

using the above properties we can write the given expressions in radical form.

13) (5x)^{-\frac{5}{4}

⇒ \frac{1}{(5x)^{\frac{5}{4}}}   [Using rule of negative exponents]

⇒ \frac{1}{\sqrt[4]{(5x)^5}}    [writing in radical form]

15) (10n)^{\frac{3}{2}

⇒ \sqrt{(10n)^3}     [Since 2nd root is given as \sqrt{} in radical form]

3 0
3 years ago
ITTTTSSSS TTTTTIIIMMMEDDD!!!Graph the function y = x3 + 3x2 – x – 3. Which lists all of the turning points of the graph?
Aleks04 [339]
I cannot do turning points.
Also, if this is from a test, it can be removed.

But here is a graph of the function.


7 0
3 years ago
Read 2 more answers
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