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harkovskaia [24]

3 years ago

13

Find the value of x (please help)

1 answer:

notka56 [123]3 years ago

5 0

Answer:

ok

Step-by-step explanation:

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Select Equal or Not Equal to correctly classify each statement.

Black_prince [1.1K]

The first problem is true because with multiplication it doesn't matter which order it is in.

The second problem is false because you will get a different quotient depending on which numbers are on which side of the equation.

3 0

3 years ago

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When a number is divided by -3, the result is 12 more than the number what is the number?

olga55 [171]

X/-3 = 12 + x
x = -36 - 3x
4x = 36
x= = 9

The number is 9.

8 0

3 years ago

(csc x - 1) (csc x + 1)

victus00 [196]

<h2>Explanation:</h2>

Here we have the following expression:

$(csc x - 1) (csc x + 1)$

So we need to extend this. Remember that the difference of squares tells us:

$(a-b)(a+b)=a^2-b^2$

So here:

$a=cscx \\ \\ b=1$

Thus:

$(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}$

4 0

3 years ago

Find the slope of the line on the graph. Write yoyur answer as a frction or a whole number, not a mixed number or decimal.

BigorU [14]

Okay, so I'm almost positive the slope is m=1/1. I know this because the line rises one and runs one.

7 0

2 years ago

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Consider the equation: 12x=13-x^212x=13−x 2 12, x, equals, 13, minus, x, squared 1) Rewrite the equation by completing the squar

Flauer [41]

Answer:

$(x + 6)^2 = 49$

$x = 1$ or $x = -13$

Step-by-step explanation:

Given

$12x = 13 - x^2$

Using Completing the Square

$12x = 13 - x^2$ ---- Add $x^2$ to both sides

$x^2 + 12x = 13 - x^2 + x^2$

$x^2 + 12x = 13$

Divide the coefficient of x by 2; then add the square to both sides

$x^2 + 12x + 6^2 = 13 + 6^2$

$x^2 + 12x + 36 = 13 + 36$

$x^2 + 12x + 36 = 49$

Factorize

$x^2 + 6x + 6x + 36 = 49$

$x(x + 6) + 6(x + 6) = 49$

$(x + 6)(x + 6) = 49$

$(x + 6)^2 = 49$

Hence, the equation is $(x + 6)^2 = 49$

Solving further

Take square root of both sides

$(x + 6) = \sqrt{49}$

$x + 6 = \±7$

$x = \±7- 6$

This implies that

$x = 7 - 6$ or $x = -7 -6$

$x = 1$ or $x = -13$

HEnce, the solutions are $x = 1$ or $x = -13$

6 0

2 years ago