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3 years ago

How do you order two numbers written in scientific notation?

Mathematics

2 answers:

tresset_1 [31]3 years ago

4 0

The correct answer is C

aivan3 [116]3 years ago

3 0

Answer:

Step-by-step explanation:

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I have to write the slope and equation of each line pictured in y = mx + b form.

Brut [27]

Answer:

y=7/3x+8

Step-by-step explanation:

You have to start at the 3and rise all the way to the 8 which is 7 and then run which is 3 so the slope mx is 7/3x. To find b which is the y intercept find the point where the line hits the y-axis.

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3 years ago

Identify the slope and y-intercept of the lins given by the equation y=2x 1.

VLD [36.1K]

Answer 2 I took the test

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3 years ago

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gavmur [86]

Answer:

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Step-by-step explanation:

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3 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago

Marta hopes to have a test average of at least 90 by the end of the marking period. Her grades on the first four tests have been

Virty [35]

Answer:

Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

Explanation:

Marks received by Marta in four tests = 86, 84, 97 and 89

Let mark received in fifth test be x

We have average of five test is more than or equal to 90

So we have

$\frac{86+84+97+89+x}{5} \geq 90\\ \\ 86+84+97+89+x\geq 450\\ \\ x\geq 94$

So Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

5 0

2 years ago