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Answer:
Area of the given triangle = 6.51 ft²
Step-by-step explanation:
If we redraw the triangle as shown in the figure attached we get the height of the triangle as x feet and base = 4.3 feet
Therefore area of ΔABC = (1/2) × Height (AD) × Base(BC)
From ΔABD
sin 53 = AD/AB = x/3.8
x = 3.8 × sin 53
= 3.8 × 0.7986 = 3.03 feet
Now area of ΔABC = (1/2)×3.03×4.3 = 6.51 feet²
