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IRISSAK [1]
3 years ago
14

Rewrite the function translated left 2 and up 4.

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

-3x +4=x-2,.........

Step-by-step explanation:

If it's wrong....I apologize in advance!

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Your on a roller coaster your velocity is 13 ft./s are you moving up or down what is your speed
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Your speed is 13 ft/sec.  In order to know our velocity, we would need to know what direction we're moving.  You haven't told us anything about our direction, only that our speed is 13 ft/sec.
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3 years ago
A quality inspector inspect random box of 50 tablets. He discovers 2 are defective. In an order of 2,000 tablets,how many are li
oksano4ka [1.4K]

Answer:

80

Step-by-step explanation:

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Which answer best describes (n k)
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3 years ago
The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
2 years ago
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