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Mamont248 [21]
3 years ago
7

A line that crosses parallel lines to create pairs of congruent and supplementary angles

Mathematics
1 answer:
jenyasd209 [6]3 years ago
7 0

Answer:

A traversal

Step-by-step explanation:

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Kjnhbgvnfcbvhjnkml,;'.<br> ?}{:HJUbmgfcbdxvsc
Sergio [31]

Answer:

$3 for 1 book.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
6) 2(n + 5) = -2<br> help i wasn’t paying attention in my google meet
bonufazy [111]

Answer: the answer is -6

2(n+5) = -2

2n + 10 = -2

2n = -2 - 10

2n = -12

2n *1/2 = -12 * 1/2 = -6

n = -6

5 0
3 years ago
Read 2 more answers
Can someone help me with this
insens350 [35]
Let's solve this problem step-by-step.

STEP-BY-STEP EXPLANATION:

We will be using simultaneous equations to solve this problem.

The sum of angles on a straight line is 180°.

( R ) and ( 2x + 5 ) are both on the same straight line.

Therefore:

Equation No. 1 -

R + 2x + 5 = 180

R = 180 - 2x - 5

R = 175 - 2x

Vertically opposite angles are equivalent to each other.

( R ) is vertically opposite ( 3x + 15 ).

Therefore:

Equation No. 2 -

R = 3x + 15

Substitute the value of ( R ) from the first equation into the second equation to solve for ( x )

R = 3x + 15

175 - 2x = 3x + 15

- 2x - 3x = 15 - 175

- 5x = - 160

x = - 160 / - 5

x = 160 / 5

x = 32

Next we will substitute the value of ( x ) from the second equation into the first equation to solve for ( R ).

Equation No. 2 -

R = 175 - 2x

R = 175 - 2 ( 32 )

R = 175 - 64

R = 111

FINAL ANSWER:

Therefore, the answer is:

R = 111

x = 32

Hope this helps! :)
Have a lovely day! <3
7 0
4 years ago
A science experiment calls for a mixture of 400 mL of liquid A, 2.5 L of liquid B, 650 mL of liquid C, and 1 L of liquid D. Whic
IceJOKER [234]

Answer:

5L.

Step-by-step explanation:

This is because there are 1000 mL in an L so .4 + 2.5 + .65 + 1 = 4.55 which is then rounded up to 5L.

5 0
3 years ago
Which quadratic equation has solutions x=8 and x=−1?
andrezito [222]
There are two ways you can do this

Using the formula


{x}^{2}  - (sum \: of \: roots)x + poduct \: of \: roots = 0

{x}^{2}  - (8+-1)x +  - 1 \times 8 = 0


{x}^{2}  - 7x  - 8 = 0


Working backwards


x = 8 \: or \: x =  - 1
\Rightarrow x-8=0  \: or  \: x+1=0

\Rightarrow (x-8)(x + 1)=0
\Rightarrow  {x}^{2}   + x -8x - 8 = 0
\Rightarrow  {x}^{2}  - 7x - 8 = 0
7 0
4 years ago
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