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Finger [1]
3 years ago
5

Continue this pattern of shapes for three more steps.

Mathematics
2 answers:
kipiarov [429]3 years ago
7 0

Answer:

Step-by-step explanation:

1. six equal sides  -Regular hexagon.

2.seven equal sides-Regular heptagon.

3. eight equal sides-Regular Octagon

marusya05 [52]3 years ago
6 0

Answer:

triangle square hexagon, triangle square hexagon

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Can someone help me with this please? I will mark you brainliest
lina2011 [118]

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

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On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Step-by-step explanation:

6 0
3 years ago
A student who is 5 ft 6 in. tall measured shadows
irakobra [83]

Answer:

lunar model

there really isnt anything to explain

5 0
4 years ago
Angles A and B are complementary and in ratio of 3:6. What is the measure of each angle
pashok25 [27]

complementary angles add up to 90°, so therefore we know that ∡A + ∡B = 90°, and also they are in a ratio of 3:6.


\bf \cfrac{A}{B}=\cfrac{3}{6}\implies \cfrac{A}{B}=\cfrac{1}{2}\implies 2A=\boxed{B}
\\\\[-0.35em]
~\dotfill\\\\
A+B=90\implies A+\boxed{2A}=90\implies 3A=90\\\\\\ A=\cfrac{90}{3}\implies \blacktriangleright A=30 \blacktriangleleft
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
2(30)=B\implies \blacktriangleright 60=B \blacktriangleleft

7 0
3 years ago
Which expression is equivalent to (4x^4/2x^3)
gavmur [86]

Answer:

2x

Step-by-step explanation:

Given

\frac{4x^4}{2x^3}

= \frac{4}{2} × \frac{x^4}{x^3}

= 2 × x^{(4-3)}

= 2x

3 0
3 years ago
If f(x)=3|x-2|, what is f(5.9)? a: 9 b: 10 c: 11 d: 12
Mice21 [21]
|a|=  \left\{\begin{array}{ccc}a&if&a\geq0\\-a&if&a \ \textless \  0\end{array}\right\\\\f(x)=3|x-2|\\\\f(5.9)=3|5.9-2|=3|3.9|=3\cdot3.9=11.7
7 0
3 years ago
Read 2 more answers
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