Answer:
exact form: 4/9
decimal form: 0.4 repeating
i hope this helps :)
0 dude it's 0. I know now you know.
The last digit of the product of all the numbers between 11 and 29 is 0.
A product is something that has undergone one or more multiplications.
Here, we're looking for the final digit of the product of all whole numbers greater than 11 and less than 29.
Next, we have the product as: 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28
Now take note of the 20 that is present.
Any number multiplied by 20 will result in a zero, so:
Product = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)
Using only that, we can infer that 0 represents the final digit in the product of all the numbers between 11 and 29.
Learn more about product here:
brainly.com/question/10873737
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Answer: For 95% Confidence Interval:
Upper Limit = 110.2
Lower Limit = 97.8
95% Confidence Interval = [97.8, 110.2]
Step-by-step explanation:
Given that,
Mean(M) = 104
Standard Deviation(SD) = 10
Sample Size(n) = 10
Formula for calculating 95% Confidence Interval are as follows:
Standard error(SE) =
= 
= 3.164
⇒ M ± 
× SE
= 104 ± (1.96)(3.164)
= 104 ± 6.20
∴ Upper Limit = 104 + 6.20 = 110.2
Lower Limit = 104 - 6.20 = 97.8
So,
95% Confidence Interval = [97.8, 110.2]
