If A = (0,2,3,4,9,11), B = {2,3,6,8,9,10) and C= {0,2,3,9), then (A-B) n(A-C) is
timofeeve [1]
Answer:
(A-B)n(A-C) ={ }
<h3><em>hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em>.</em></h3>
<em>Wishing</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>.</em>
(3,7),(-3,-5)
that’s what it would look like on a graph
Answer:
140
Step-by-step explanation:
When working HCF and LCM problems, I like to think in terms of this little diagram:
(a [ b ) c]
It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.
__
Here, we're given ...
b = 20
ab = 320
abc = 2240
Then ...
c = abc/(ab) = 2240/320 = 7
x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320
x = 140
I spent a lil time on it but I’ll let you know in a lil but if I have the answer:)
