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ra1l [238]
3 years ago
15

Please help me with this problems before my head explodes

Mathematics
1 answer:
Orlov [11]3 years ago
4 0

Answer:

1: c over 3

2: 9

3: 15 square root of 3

4: 5 + 2√6

Sorry but that's all I got

Step-by-step explanation:

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The beam should be placed 8 feet from the center.

Step-by-step explanation:

The struts are y = √(x + 8) and y = √(x − 4).  The struts are 2 feet apart at the location of the beam:

√(x + 8) − √(x − 4) = 2

Solving:

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8 0
3 years ago
The difference between two numbers is 12. Four times the larger number decreased by 25 equals 48 increased by 3 times the smalle
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Step-by-step explanation:

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The difference between two numbers is 12.  Three times the larger number is seven times the smaller.  What are the two numbers? 

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Expert Answers info

JEEW-M  | CERTIFIED EDUCATOR

Let us say the two numbers are x and y and x>y.

The data we have are;

Difference between the numbers are 12.

3 times larger number is equal to 7 times smaller number.

Then we can write;

 ----(1)

 ----(2)

 

From (1) we can say 

Then substituting  to (2) gives;





      

        

 

Then;





7 0
3 years ago
Will an exponential function always, never, or sometimes exceed a polynomial function?
patriot [66]
At some point, the exponential function always exceeds a polynomial function.
3 0
3 years ago
Read 2 more answers
If
Dovator [93]

12^2=144

144 is divided by b which also is an odd interger, there only 2 numbers : 1 and 3

if b=3, a^2=48, then there will be no a available

if b=1 , a^2=144, then a is 12 and 12 can not be divided by 9

The answer is D

3 0
3 years ago
The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true
Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478

<u>Part B</u>

P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767

<u>Part C</u>

\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971

6 0
2 years ago
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