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3 years ago

Please help me with this problems before my head explodes

Mathematics

1 answer:

Orlov [11]3 years ago

4 0

Answer:

1: c over 3

2: 9

3: 15 square root of 3

4: 5 + 2√6

Sorry but that's all I got

Step-by-step explanation:

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As an estimation we are told £3 is €4.

poizon [28]

Answer:

€113.87

Step-by-step explanation:

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WILL MARK BRAINLIEST!! Which of the following ordered pairs are y-intercepts? Check all that apply.

Y_Kistochka [10]

Y intercept is where the line meets the Y axis
So the points shd be in (0,y) form.

So (0,0) (0,-7) (0,-0.25) are the y-intercepts in the following.

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horsena [70]

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Step-by-step explanation:

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part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.

andreev551 [17]

Answer: $\bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}$

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

$5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

$6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}$

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

$7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}$

Note: hypotenuse not needed for tan

$8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}$

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10

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3 years ago

Whenever 2 line or intersect at 90 the 2 lines are said to be ?

Sedaia [141]

Two lines that intersect at 90 degrees are considered perpendicular to each other.

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4 years ago

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