By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is 
<h3>What is
sequence ?</h3>
Sequence is collection of numbers with some pattern .
Given sequence
We can see that
and
Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2
Now 
term of this Geometric progression can be written as
So summation of 15 terms can be written as
By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is
To learn more about Geometric progression visit : brainly.com/question/14320920
Answer:
4.56
Step-by-step explanation:
After this equation is simplified, it is solved the way any 1-step linear equation is solved.
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1.4t -0.4(t -3.1) = 5.8 . . . . . . given
1.4t -0.4t +1.24 = 5.8 . . . . . eliminate parentheses
t +1.24 = 5.8 . . . . . . . . . collect terms (now you have a 1-step equation)
t = 4.56 . . . . . . . . . .subtract 1.24
Answer:
4/7x - 5 ________________________________________
Answer: 14x^2-93xy+60y^2 Hope that helps!
Step-by-step explanation:
1. Expand by distributing terms
(20x-12y)(x-4y)-(3x-4y)(2x+3y)
2. Use the Foil method:(a+b)(c+d)= ac+ad+bc+bd
20x^2-80xy-12yx+48y^2-(3x-4y)(2x+3y)
3. Use the Foil method : (a+b)(c+d)= ac+ad+bc+bd
20x^2-80xy-12yx+48y^2-(6x^2+9xy-8yx-12y^2)
4. Remove parentheses 20x^2-80xy-12yx+48y^2-6x^2-9xy+ 8yx+12y^2
5. Collect like terms (20x^2-6x^2)+(-80xy-12xy-9xy+8xy)+(48y^2+12y^2)
6. Simplify.
And your answer would be 14x^2-93xy+60y^2
