Question

Please help me these right now.

Answer 1

49. From 3 coin tosses, there are 8 possible outcomes:

... TTT, TTH, THT, THH, HTT, HTH, HHT, HHH

All but the first have at least one head, so 7/8 of the possibilities have at least one head. That's 87.5% (not among your choices).

Likewise, all but the last listed outcome have at least one tail. The problem is symmetrical that way when the coin is fair. 87.5% of outcomes have at least one tail.

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Perhaps you can tell I read your question as having two parts. If your question is the probability of getting at least one head AND at least one tail, you can see that condition includes 6 of the 8 outcomes, or 75%, matching selection d.

50. See for yourself: the calculator says 66.82%. Your best choice is selection d.