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dolphi86 [110]
3 years ago
14

2x+2y=10 solve for x

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Isolate the x. Note the equal sign. What you do to one side you do to the other.


Subtract 2y from both sides


2x + 2y (-2y) = 10 (-2y)


2x = 10 - 2y


Isolate the x, divide 2 from both sides and from all terms.


(2x)/2 = (10 - 2y)/2


x = 5 - y


Place the variable in the front


x = -y + 5


x = -y + 5 is your answer


hope this helps

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\qquad\qquad\huge\underline{{\sf Answer}}♨

As we know ~

Area of the circle is :

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

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➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

<h3>Problem 1</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 4.4\div 2

\qquad \sf  \dashrightarrow \:r = 2.2 \: mm

Now find the Area ~

\qquad \sf  \dashrightarrow \: \pi {r}^{2}

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\qquad \sf  \dashrightarrow \:3.14 \times  {4.84}^{}

\qquad \sf  \dashrightarrow \:area  \approx 15.2 \:  \: mm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 2</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 3.7 \div 2

\qquad \sf  \dashrightarrow \:r = 1.85 \:  \: cm

Bow, calculate the Area ~

\qquad \sf  \dashrightarrow \: \pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (1.85) {}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 3.4225 {}^{}

\qquad \sf  \dashrightarrow \:area  \approx 10.75 \:  \: cm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>Problem 3 </h3>

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (8.3) {}^{2}

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\qquad \sf  \dashrightarrow \:area \approx216.31 \:  \: cm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>Problem 4</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

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now, let's calculate area ~

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・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 5</h3>

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・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 6</h3>

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➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

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