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3 years ago

14

2x+2y=10 solve for x

1 answer:

irakobra [83]3 years ago

7 0

Isolate the x. Note the equal sign. What you do to one side you do to the other.

Subtract 2y from both sides

2x + 2y (-2y) = 10 (-2y)

2x = 10 - 2y

Isolate the x, divide 2 from both sides and from all terms.

(2x)/2 = (10 - 2y)/2

x = 5 - y

Place the variable in the front

x = -y + 5

x = -y + 5 is your answer

hope this helps

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$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

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$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

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・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

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$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

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・．━━━━━━━†━━━━━━━━━．・

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