Let x = length of the park
Let y = width of the park
Because the area is 392392 ft², therefore
xy = 392392 (1)
Because three sides of fencing measure 5656 ft, therefore
2x + y = 5656 (2)
That is
y = 5656 - 2x (3)
Substitute (3) into (1).
x(5656 - 2x) = 392392
5656x - 2x² = 392392
2x² -5656x + 392392 = 0
x² - 2828x + 196196 = 0
Solve with the quadratic formula.
x = (1/2)*[2828 +/- √(2828² - 4*196196)]
= 2756.83 or 71.17
Answer:
The possible dimensions are 2756.8 ft and 71.2 ft (nearest tenth)
Angles LMO and NMO are congruent, of equal measures,
x=15
A percent between 25 and 50 can be 35%
35% as a decimal is 0.35
35% as a fraction = 35/100
35/100 simplest form = 7/20
hope this helps
Division first (16\8)=2+10=12 (9+3 = 12 ) 12+12= 24
Answer: 10
Solution:
60/12 = 5
2 x 5 = 10
