56 is what I got.
Hope this helps
The volume of the cone is 3.14 x 14 x 14
Answer:
Step-by-step explanation:
Given
The attached triangle
Required
Find h, x and y
Let the base of the triangle be 15.
So, the area is:
Let the base of the triangle be 25.
So, the area is:
Substitute
Solve for h
Considering the smallest triangle
So:
This gives:
Take square roots
Solving for y
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Tom arranged 3 groups of 4
