<span>If "ALABAMA" were written so that the A's were of different colors, the number of permutations would be 7!. However,
since the four A's look exactly alike in "ALABAMA", the number of
distinguishable permutations is much smaller. So what we do is start
with the 7! arrangements of "ALABAMA", and divide by the number of ways
the four A's can be arranged within each permutation, so that in effect
they will all be counted only once.
So the answer is
=7!/4!
</span><span>=5040/24
= 210. </span>
The answer is D because it passes the horizontal line test.
Answer:3 lines could be used
Step-by-step explanation:
You need 2 points to draw a line. The order doesn't really matter. Line AB is the same as line BA. The problem is to select 2 points out of 3 to draw different lines. If we do the same to the others, we get the following pairs of points to draw lines.
AB , AC
BA , BC
CA , CB
which is only 3 lines
Answer:
(m - 7) + 15
Step-by-step explanation: