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aliya0001 [1]
3 years ago
9

Please help on two math questions. I don’t understand how to do them.

Mathematics
1 answer:
Sidana [21]3 years ago
3 0

When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.

In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be

x\leq -2 \lor\ x>1

or, in interval notation,

(-\infty,-2]\cup (1,\infty)

In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.

This means that the difference between your numbers at 1 must be at most 4, which is modelled by

|x-1|\leq 4

where the absolute values guarantees that you'll pick numbers to the left and to the right of 1.

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Jared and Peter can share a bag of Gummy Worms
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Alenkasestr [34]

Answer:

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Step-by-step explanation:

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3 years ago
A confectioner has 300 pounds of a chocolate that is 1 part cocoa butter to 7 parts caramel. How much chocolate that is 1 part c
anygoal [31]
Let's call our unknown quantity n. We'll need to add n lbs of chocolate with a 1/15 ratio of cocoa butter to caramel to 300 lbs of chocolate with a 1/7 ratio of cocoa butter to caramel to yield 300+n lbs of chocolate with a 1/9 ratio of cocoa butter to caramel. We can set this up as an equation, but it's important to note something first: the ratio of the <em>caramel to the cocoa butter</em> is provided, but this is not the same thing as the <em>fraction of the chocolate the cocoa butter takes up</em>.

The 300 pounds of chocolate have 1 + 7 = 8 parts of cocoa butter and caramel total, which means that cocoa butter takes up 1/8 of those total parts; the n pounds we're adding on has 1 + 15 = 16 total parts, which means the cocoa butter takes up 1/16 of those; and the 300+n pounds being produced have 1 + 9 = 10 total parts, so the cocoa butter takes up 1/10 of those parts. With this in mind, we can set up the following equation:

300\big( \frac{1}{8}\big)+n\big( \frac{1}{16}\big)=(300+n)\big( \frac{1}{10}\big)

which we can rewrite as

\frac{300}{8}+ \frac{n}{16}= \frac{300+n}{10}

From here, it would be helpful to combine the fractions on the left side of the equation. To do this, we'll convert the denominator of \frac{300}{8} to 16, multiplying it by \frac{2}{2} to obtain the fraction \frac{600}{16}. Combining that with \frac{n}{16}, we have:

\frac{600+n}{16}= \frac{300+n}{10}

To get rid of the denominator on the left, we'll multiply both sides of the equation by 16, and to eliminate the one on the right, we'll multiply both sides by 10:

(10)(16)\big( \frac{600+n}{16}\big)=\big( \frac{300+n}{10}\big)(10)(16)

Simplifying:

10(600+n)=(300+n)16\\ 6000+10n=4800+16n

And finally, we solve for n:

6000-4800=16n-10n\\ 1200=6n\\ 200=n

So, the confectioner needs 200 lbs of chocolate that's 1 part cocoa butter and 15 parts caramel.
8 0
4 years ago
31. The length of a rectangle is 2 meters less than
Effectus [21]

Answer:

l=15

Step-by-step explanation:

let length=l

width=w

l=3w-2

w=(l+2)/3

Perimeter P=2(l+w)=2[l+(l+2)/3]=2(4l+2)/3≤43

2(4l+2)≤129

8l+4≤129

8l≤125

l≤125/8

so l=15

________________

P=2(l+w)=2(3w-2+w)=8w-4≤43

8w≤47

w≤47/8

l≤141/8-2

l≤125/8

l=15

8 0
3 years ago
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worty [1.4K]
37 cherry pies for at least 100 dollar profit
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3 years ago
Read 2 more answers
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