All categories

3 years ago

Which ordered pair is a solution to the system

Mathematics

1 answer:

MaRussiya [10]3 years ago

3 0

9514 1404 393

Answer:

(3, 1)

Step-by-step explanation:

The lines on the graph cross at the point (x, y) = (3, 1). That is the solution to the system of equations.

You might be interested in

How many times does 8 go into 153

butalik [34]

8 goes into 153 19 times.

4 0

3 years ago

Read 2 more answers

Estimate The Square root of 59

Strike441 [17]

Step-by-step explanation: To estimate the value of the square root of 59, we know that the square root of 49 is 7 and the square root of 64 is 8. This means that the square root of 59 must have a value between 7 and 8.

8 0

3 years ago

Is 2/9 closer to 1/2 or 1 or 0

SVEN [57.7K]

2/9=0.222
The answer would be 0.

8 0

4 years ago

Read 2 more answers

Can anyone solve this please asap

Reika [66]

Answer:

Step-by-step explanation:

= (3 + √3) (2 - √3)

= 6 - 3√3 + 2√3 - 3

= 3 - 3√3 + 2√3

= 3 - √3 (3 - 2)

= 3 - √3

= 3 - 1.732 ...... (√3 = 1.732)

= 1.268

6 0

2 years ago

GCSE 995381

nikdorinn [45]

Answer:

$2.9 cm^2$

Step-by-step explanation:

Given,

Angle of sector = 30°

Radius of circle, r = 8 cm

Area of the shaded region, A =?

The diagram is attached below.

Now,

Area of shaded region = Area of sector - Area of triangle

Area of triangle = $\frac{1}{2}\times base \times height$

We know that,

$\sin \theta = \dfrac{P}{H}$

$\sin 30^\circ= \dfrac{P}{8}$

$P = \dfrac{8}{2}$

$P = 4\ cm$

And

$\cos \theta =\dfrac{B}{H}$

$\cos 30^\circ = \dfrac{B}{8}$

$B = \dfrac{8\times \sqrt{3}}{2}$

$B = 4\sqrt 3$

Area of sector = $\dfrac{\theta}{360^\circ}\times \pi r^2$

Area of sector = $\dfrac{30^\circ}{360^\circ}\times \pi \times 8^2$

= 16.75 cm^2

Area of triangle = $\dfrac{1}{2} \times 4\sqrt 3 \times 4$

= 13.85 cm^2

Area of shaded region = 16.75 - 13.85

= $2.9 cm^2$

7 0

2 years ago