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3 years ago

Help hurry plz. !!!!!!!!!!!!!!!

Mathematics

2 answers:

Kobotan [32]3 years ago

6 0

2 I think .................

Oduvanchick [21]3 years ago

3 0

Answer:

after 6 hours

Step-by-step explanation:

Since no method is specified, we write a table.

After n hours distance car 1 distance car 2

0 0 0

1 40 miles 0

2 80 miles 0

3 120 miles 0

4 160 miles 60 miles

5 200 miles 120 miles

6 240 miles 180 miles

7 280 miles 240 miles

8 320 miles 300 miles

9 360 miles 360 miles

The second car leaves at hour 3 and catches up to the first car at hour 9.

9 - 3 = 6.

Answer: after 6 hours

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3 years ago

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polet [3.4K]

Answer:

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3 years ago

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After the bank cashed a check Maureen wrote for $60, her balance was -$14. The equation

Andrew [12]

Answer:

The initial cash balance in bank is $46

Step-by-step explanation:

The equation given to determine b which is the initial money before she withdrew $60 is

b + (-60) = -14

Let's solve for the value of b which is the initial balance of the money in the bank.

b + (-60) = -14

b -60 = -14

b = -14+60

b = 60-14

b = 46

The initial money before she withdrew $60 was $46

8 0

3 years ago

A group of students are planning a mural at a wall the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning

zvonat [6]

Answer: $46x^2+73x+15$

Step-by-step explanation:

The area of a rectangle can be calculated with the formula:

$A=lw$

l: the length of the rectangle.

w: the width of the rectangle.

The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.

Knowing that the dimensions of the wall are $(6x+7)$ by $(8x+5)$ , its area is:

$A_w=(6x+7)(8x+5)\\\\A_w=48x^2+30x+56x+35\\\\A_w=48x^2+86x+35$

As they are planning that the dimensions of the mural be $(x+4)$ by $(2x+5)$ , its area is:

$A_m=(x+4)(2x+5)\\\\A_m=2x^2+5x+8x+20\\\\A_m=2x^2+13x+20$

Then the area of the remaining wall after the mural has been painted is:

$A_{(remaining)}=A_w-A_m\\\\A_{(remaining)}=48x^2+86x+35-(2x^2+13x+20)\\\\A_{(remaining)}=48x^2+86x+35-2x^2-13x-20\\\\A_{(remaining)}=46x^2+73x+15$

8 0

3 years ago

Answer step by step

enot [183]

Consider, please, this solution/explanation:
1. suppose, that number of cars is 'x', numbers of buses is 'y'.
2. according to the condition 'a total of 32', it means that x+y=32. This is the 1st equation.
3. according to the condition in one car are 3x persons, in one bus are 27y persons, and totaly 3x+27y=408 people. This is the 2d equation.
4. if to solve the system of two equations:
$\left \{ {{x+y=32} \atop {3x+27y=408}} \right. \ =\ \textgreater \ \ \left \{ {{x=19 (cars)} \atop {y=13(buses)}} \right.$

Answer: 13 - b., 19 - c.

6 0

3 years ago