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Svet_ta [14]
3 years ago
9

Need help asaphsjshsuehdue​

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0
My did ask the ppl who make Big Macs
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Please help me with this question
Maslowich

The answer is 6 feet

3 0
3 years ago
Mr. Galloway purchased a car for $20,000. The car retains 85% of its value each year. How much will the car be worth in 5 year?
katrin [286]
Try with 9,135, I think this one is correct
7 0
3 years ago
26.<br> 12/2(x+6)=2x-9<br> 21
Stella [2.4K]

\frac{12}{2} (x+6)=2x-9

6x+36=2x-9

<h2>6x - 2x = -9 + 36</h2>

4x = -45

x = -\frac{45}{4}

Hope that I helped you!

6 0
1 year ago
Given that the four points A(1,2), B(2, -5), C(7,0) and D(p,q) are the vertices of the rhombus ABCD
Serga [27]

Step-by-step explanation:

Three coordinates of a Rhombus is given to us. And the fourth coordinate is D(p,q) . Weneedtofind the value of p and q . We know that the diagonals of Rhombus bisect each other at right angles . So lets find the midpoint.

<u>•</u><u> </u><u>Midpoint</u><u> </u><u>of</u><u> </u><u>AC</u><u> </u><u>:</u><u>-</u><u> </u>

\tt\to Midpoint_{(AC)}= \bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\tt\to Midpoint_{(AC)}= \bigg( \dfrac{1+7}{2},\dfrac{2+0}{2}\bigg)\\\\\tt\to Midpoint_{(AC)}= \bigg(\dfrac{8}{2},\dfrac{2}{2}\bigg)\\\\\tt\to \boxed{\orange{\tt Midpoint_{(AC)}= (4,1)}}

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>• Midpoint of </u><u>BD</u><u> :- </u>

\tt\to Midpoint_{(BD)}= \bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\tt\to \boxed{\orange{\tt Midpoint_{(BD)}= \bigg( \dfrac{2+p}{2},\dfrac{q-5}{2}\bigg)}}

<u>_______________________________</u>

Now since these two coordinates must be equal, therefore ,

\tt\to \bigg(  \dfrac{2+p}{2},\dfrac{q-5}{2}\bigg)= (4,1)\\\\\tt\to \dfrac{2+p}{2}=4 \qquad and \qquad \dfrac{q-5}{2}=1 \\\\\tt\to 2 + p = 8 \qquad and \qquad q-5 = 2 \\\\\tt\to p = 8 -2 \qquad and \qquad q = 2 +5 \\\\\tt\to\boxed{\orange{\tt (p,q) = (6,7) }}

3 0
3 years ago
4. Construct a quadrilateral ABCD in which AB=BC=3.5cm, AD=CD= 5.2 cm and ^ABC= 120°.
Paul [167]

9514 1404 393

Explanation:

The attachment shows such a construction. Here are the steps.

1. Draw circle B with radius 3.5 cm

2. Mark a point X on the circle and draw circle X with the same radius. Mark the intersection points of circles B and X as points A and C.

3. Draw circles A and C with radii 5.2 cm. Mark the intersection point as point D so that X is on segment BD.

4. Finish by drawing kite ABCD.

5 0
3 years ago
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