Answer:
Listed
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Answer:
No Solution
Step-by-step explanation:
| −2n | + 10 = −50
Subtract 10 on both sides
|-2n|+10-10=-50-10
Simplify
|-2n=|=-60
No Solution
Answer:
B
Step-by-step explanation:
The number is between 10 and 49
The number is divisible by 3
Let the 10s digit = x
Let the units digit = y
1/3 * (10x + y) = x + y multiply both sides by 3
10x + y = 3(x +y) remove the brackets.
10x +y = 3x + 3y Subtract 3x from both sides
10x - 3x + y = 3y Combine\
7x + y = 3y Subtract y from both sides.
7x = 3y - y Combine
7x = 2y
x can't be very big. Even taking 1/3 will get out of range is you use 6.
Also x should be an even number. The units digit cannot have a fraction in it.
Try making x = 2
7*2 = 2*y
14 = 2y Divide by 2
14/2 = y
y = 7
So the number is possibly 27. Let's check it out.
- The number is between and includes 10 and 49. 27 is between these two endpoints.
- 27 is divisible by 3
- 1/3(27) = sum of digits
- 9 = (2 + 7)
All of the conditions are met. It's B
Sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
As given,
Let a-d, a, a +d be three numbers
Sum =33
⇒a-d + a +a +d =33
⇒ a =11
Sum of cubes= 5049
⇒ (a-d)³ + a +(a +d)³ =5049
⇒ a³ -d³ -3a²d +3ad² + a³ +a³ +d³ +3a²d +3ad² =5049
⇒3a³ + 6ad² = 5049
⇒ d=± 4
Therefore, sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
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