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3 years ago

I need help with this math

Mathematics

2 answers:

Anit [1.1K]3 years ago

6 0

Answer:

x=9 y=-4

Step-by-step explanation:

1) to eliminate a variable make sure they are the same so you can cancel them out

lets eliminate x

-3 and -2 share a GCF of 6 so

2(-3x-4y=-11)

-6x-8y=-22

3(-2x-6y=6)

-6x-18y=18

-6x-8y=-22

-6x-18y=18

--------------------------

10y=-40

y=-4

2)substitute y as -4 in the second equation

-2x-6(-4)=6

-2x+24=6

-2x=-18

x=9

Burka [1]3 years ago

6 0

Answer:

(9,-4)

Step-by-step explanation:

$(-3x-4y=11)*-2(-2x-6y=6)*3\\6x+8y=22-6x-18y=18\\ 6x and -6x cancel out-10y=40 y=-4 \\Plug -4 for y. -2x-6(-4)=6 -2x+24=6 -24 -24 -2x=-18 x =-9$

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Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

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$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

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Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

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3 years ago

I need help with this math​

I need help with this math