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3 years ago

I need help with this math

Mathematics

2 answers:

Anit [1.1K]3 years ago

6 0

Answer:

x=9 y=-4

Step-by-step explanation:

1) to eliminate a variable make sure they are the same so you can cancel them out

lets eliminate x

-3 and -2 share a GCF of 6 so

2(-3x-4y=-11)

-6x-8y=-22

3(-2x-6y=6)

-6x-18y=18

-6x-8y=-22

-6x-18y=18

--------------------------

10y=-40

y=-4

2)substitute y as -4 in the second equation

-2x-6(-4)=6

-2x+24=6

-2x=-18

x=9

Burka [1]3 years ago

6 0

Answer:

(9,-4)

Step-by-step explanation:

$(-3x-4y=11)*-2(-2x-6y=6)*3\\6x+8y=22-6x-18y=18\\ 6x and -6x cancel out-10y=40 y=-4 \\Plug -4 for y. -2x-6(-4)=6 -2x+24=6 -24 -24 -2x=-18 x =-9$

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Which expression is equivalent to Negative 2 and one-fourth divided by negative two-thirds?

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Negative 2 and one-fourth divided by negative two-thirds is equivalent to $\frac{-2+\frac{1}{4}}{-\frac{2}{3}}$ and simplified into $=\frac{21}{8}$

Step-by-step explanation:

We need to find the equivalent expression of Negative 2 and one-fourth divided by negative two-thirds

Basically we will translate it into mathematical form.

Converting step by step

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and: +

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combining them we get:

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divided by negative two-thirds: $\frac{-2+\frac{1}{4} }{-\frac{2}{3} }$

So, Negative 2 and one-fourth divided by negative two-thirds is equivalent to: $\frac{-2+\frac{1}{4} }{-\frac{2}{3} }$

We can simplify the term $\frac{-2+\frac{1}{4} }{-\frac{2}{3} }$ to get simplified answer.

Simplifying:

$\frac{-2+\frac{1}{4}}{-\frac{2}{3}}$

Taking LCM of numerator

$=\frac{\frac{-2*4+1}{4}}{-\frac{2}{3}}$

$=\frac{\frac{-8+1}{4}}{-\frac{2}{3}}$

$=\frac{\frac{-7}{4}}{-\frac{2}{3}}$

Converting division into multiplication and reciprocating the denominator

$=\frac{-7}{4}\times -\frac{3}{2}$

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So, Negative 2 and one-fourth divided by negative two-thirds is equivalent to $\frac{-2+\frac{1}{4}}{-\frac{2}{3}}$ and simplified into $=\frac{21}{8}$

Keywords: Solving Expressions

Learn more about Solving Expressions at:

#learnwithBrainly

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I need help with this math​

I need help with this math