Here is a list of the odd number paired
1+3, 1+5, !+7, and !+9 (there are 4 unique sums - 4, 6,8 and 10)
3+5, 3+7, 3+9 (notice I did not pair 3 with 1 and the the only new sum is 12)
5+7, 5+9 (the only new sum is 14)
7+9 (16 is a new sum)
The sums (no repeats) are 4,6,8,10,12,14 and 16 for a total of seven numbers.
Total number of volunteer students for a committee = 7
Number of committee = 5
Number of ways of selecting the committee from the 7 volunteers = 7C5 = 7!/(5!*2!) = 21 ways.
There are 21 ways in which the 5-committee member can be selected from the 7 volunteers.
Answer:
- 3a + 6
Step-by-step explanation:
subtract and add like items together like
- 4a + a = -3a
b-b= 0
and
9-3 = 6
so the answer is
-3a +6
Answer:
A. 7
<em>good luck, i hope this helps :)
</em>